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Liono4ka [1.6K]
3 years ago
6

Solve for Y (5y + 2)(y-1) = 0

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

y = -2/5 or y = 1

Step-by-step explanation:

(5y + 2)(y-1) = 0

(5y+2) = 0

Subtract 2 on both sides.

5y = -2

Divide 5 into both sides.

y = -2/5

(y - 1) = 0

Add 1 on both sides.

y = 1

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Make m the subject in a(c+m)=2(c+3m)
Murrr4er [49]

Answer:

m = \frac{2c-ac}{a-6}

Step-by-step explanation:

distribute parenthesis on both sides

ac + am = 2c + 6m ( collect terms in m on left side )

subtract 6m from both sides

ac + am - 6m = 2c ( subtract ac from both sides )

am - 6m = 2c - ac ( factor left side )

m(a - 6) = 2c - ac ( divide both sides by (a - 6))

m = \frac{2c-ac}{a-6}


3 0
4 years ago
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
3 years ago
25x2 + 5x
poizon [28]

Answer:

option C: 5x+1

Explaination:

take 5x common and simplify

3 0
3 years ago
The table shows the relationship between the number of Calories Lucie burns while jumping rope and the number of minutes she jum
iragen [17]

Answer:

The amount of calories Lucie will burn by jumping for 1 minute is 8 calories

Step-by-step explanation:

The given data values are;

Minutes {}                  Calories Burned

40                {}            320

80        {}                    640

120 {}                          960

160 {}                          1280

The value of calories burnt and the number of minutes of jump robe are seen to be directly proportional, such that we have;

40 minutes of jump rope will yield 320 calories burnt

Therefore we have;

1 minute of jump rope will yield 320/40 = 8 calories burnt

The amount of calories Lucie will burn by jumping for 1 minute = 8 calories.

8 0
3 years ago
Translate the following sentence into equations <br> •Three less than "x" is equal to 13
Vikentia [17]
3 less then x.......x - 3
is equal to 13...= 13

x - 3 = 13 <==
3 0
3 years ago
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