Answer:
2
Step-by-step explanation:
Answer:
Tim's bean sprout grow by more than .
Step-by-step explanation:
We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.
We have to find how many more inches did Tim's bean sprout grow than Teegan's.
Firstly, converting both the mixed fractions in improper fraction get;
Tim's bean sprout grew = =
Teegan's bean sprout grew = =
Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.
Tim's bean sprout grew =
Teegan's bean sprout grew =
Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.
So, Tim's bean sprout grow by more than = =
Hence, Tim's bean sprout grow by more than .
Answer:
p = 26 ; q = 60
Step-by-step explanation:
Given the demand and supply functions :
Supply function:
4p - q = 44
Demand function :
(p + 2)q = 1680 - - - - (1)
p = price ; q = quantity
Expressing supply function interms of q
4p - 44 = q - - - - - (2)
Plug 4p - 44 = q into (1)
(p + 2) (4p - 44) = 1680
4p²- 44p + 8p - 88 = 1680
4p² - 36p - 1768 = 0
p² - 9p - 442p = 0
p(p - 26) + 17(p-26) = 0
(p + 17) = 0 ; (p - 26) =0
p = - 17 or p = 26
Price of commodity can't be negative, Hence, p = 26
From q = 4p - 44
Put p = 26
q = 4(26) - 44
q = 104 - 44
q = 60
p = 26 ; q = 60
3x^2 + 3y^2 + 12x − 6y − 21 = 0 => x^2 + y^2 + 4x - 2y - 7 = 0 => x^2 + 4x + 4 + y^2 - 2y + 1 = 12 => (x + 2)^2 + (y - 1)^2 = 12 => centre is (-2, 1)
5x^2 + 5y^2 − 10x + 40y − 75 = 0 => x^2 + y^2 - 2x + 8y - 15 = 0 => x^2 - 2x + 1 + y^2 + 8y + 16 = 32 => (x - 1)^2 + (y + 4)^2 = 32 => centre is (1, -4)
5x^2 + 5y^2 − 30x + 20y − 10 = 0 => x^2 + y^2 - 6x + 4y - 2 = 0 => x^2 - 6x + 9 + y^2 + 4y + 4 = 15 => (x - 3)^2 + (y + 2)^2 = 15 => centre is (3, -2)
4x^2 + 4y^2 + 16x − 8y − 308 = 0 => x^2 + y^2 + 4x - 2y - 77 = 0 => x^2 + 4x + 4 + y^2 - 2y + 1 = 82 => (x + 2)^2 + (y - 1)^2 = 82 => centre is (-2, 1)
x^2 + y^2 − 12x − 8y − 100 = 0 => x^2 - 12x + 36 + y^2 - 8y + 16 = 152 => (x - 6)^2 + (y - 4)^2 = 152 => centre is (6, 4)
2x^2 + 2y^2 − 8x + 12y − 40 = 0 => x^2 + y^2 - 4x + 6y - 20 = 0 => x^2 - 4x + 4 + y^2 + 6y + 9 = 33 => (x - 2)^2 + (y + 3)^2 = 33 => centre is (2, -3)
4x^2 + 4y^2 − 16x + 24y − 28 = 0 => x^2 + y^2 - 4x + 6y - 7 = 0 => x^2 - 4x + 4 + y^2 + 6y + 9 = 20 => (x - 2)^2 + (y + 3)^2 = 20 => centre is (2, -3)
3x^2 + 3y^2 − 18x + 12y − 81 = 0 => x^2 + y^2 - 6x + 4y - 27 = 0 => x^2 - 6x + 9 + y^2 + 4y + 4 = 40 => (x - 3)^2 + (y + 2)^2 = 40 => centre is (3, -2)
x^2 + y^2 − 2x + 8y − 13 = 0 => x^2 - 2x + 1 + y^2 + 8y + 16 = 30 => (x - 1)^2 + (y + 4)^2 = 30 => centre = (1, -4)
x^2 + y^2 + 24x + 30y + 17 = 0
=> x^2 + 24x + 144 + y^2 + 30y + 225 = 352 => (x + 12)^2 + (y + 15)^2 = 352 => center is (-12, -15)
Therefore, 3x^2 + 3y^2 + 12x − 6y − 21 = 0 and 4x^2 + 4y^2 + 16x − 8y − 308 = 0 are concentric.
5x^2 + 5y^2 − 10x + 40y − 75 = 0 and x^2 + y^2 − 2x + 8y − 13 = 0 are concentric.
5x^2 + 5y^2 − 30x + 20y − 10 = 0 and 3x^2 + 3y^2 − 18x + 12y − 81 = 0 are concentric.
2x^2 + 2y^2 − 8x + 12y − 40 = 0 and 4x^2 + 4y^2 − 16x + 24y − 28 = 0 are concentric.
Answer:
He must invest R297 521 today.
Step-by-step explanation:
The compound interest formula is given by:
Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.
Banabas must pay his ex-wife an amount of R350 000 in two years’ time.
This means that
Interest rate of 8.15% per annum compounded monthly:
This means that .
Amount he must invest today:
This is P. So
He must invest R297 521 today.