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lina2011 [118]
3 years ago
8

I NEED HELP I WILL MARK IT BRAINLY

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0

Answer:

W=2/(P-2L)

Step-by-step explanation:

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Assuming you mean 6x^ \frac{3}{5} and not (6x)^ \frac{3}{5}

remember
x^ \frac{m}{n}= \sqrt[n]{x^m} so

6x^ \frac{3}{5}=6 \sqrt[5]{x^3}
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Is 730.921 less than, greater than, or equal to 730,921?
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730.921 is equal to 730,921
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what quadrilateral has exactly two pairs of consecutive angles that are supplementary and none of the opposite angles are congru
Scrat [10]

Answer:

If a quadrilateral is a parallelogram, then consecutive angles are supplementary. If both pairs of opposite sides of a quadrilateral are congruent, then the quadrilateral is a parallelogram.

Step-by-step explanation:

8 0
2 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
Gianna is going to throw a ball from the top floor of her middle school. When she throws the hall from 48 feet above the ground,
vazorg [7]

Answer:

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

Step-by-step explanation:

The height h of the ball is modeled by the following equation

h(t)=-16t^2+32t+48

The problem want you to find the times the ball will be 48 feet above the ground.

It is going to be when:

h(t) = 48

h(t)=-16t^{2}+32t+48

48=-16t^{2}+32t+48

0=-16t^{2}+32t+48 - 48

16t^{2} - 32t = 0

We can simplify by 16t. So

16t(t-2)= 0

It means that

16t = 0

t = 0

or

t - 2 = 0

t = 2

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

6 0
3 years ago
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