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3 years ago

The diagonals of a kite separate the quadrilateral into four congruent triangles

1 answer:

6 0

<span>If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
hope this helps :)</span>

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Marvin spent 2.8 hours which is 35% of his time at the recreational center playing ping pong. How long was Marvin at the recreat

timofeeve [1]

Answer:

<u>3</u><u>5</u>×2.8

100

100= 0.98

6 0

3 years ago

What is the slope of a line that is perpendicular to the line whose equation is 3x+2y=6?

LekaFEV [45]

first, we can find the slope from the equation that is given buy solving the equation for y

3x+2y = 6

2y = 6-3x

y = 3-3/2x

y = -3/2x+3

now that the equation is in slope-intercept form, we can easily see that the slope of the given line is -3/2

perpendicular lines have slopes that are negative reciprocals, so we can just take the negative reciprocal of the slope we have

-3/2 → 3/2 → 2/3

the slope of the perpendicular line is 2/3

hope this helped

7 0

4 years ago

Read 2 more answers

How many bottles of chocolate can you buy with $20 if one cost $4?<br> One step equation

Ulleksa [173]

You can buy 5 bottles because $4 times 5 equals $20. I hope this helps :)

6 0

3 years ago

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If the probability of a win is 0.5 and the probability of a draw is 0.3, what is the probability of a loss?

Bad White [126]

The probability of loss is 0.2 because they must add up to 1.

7 0

4 years ago

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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Pavel [41]

$\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Explanation:</h2>

Using the quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

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3 years ago