1)
neverminding how many grams or liters...or whatever unit for now
we know one bag of grass covered 1/6 of the lawn, "a whole" or 1, is 6/6
if 1 bag covers 1/6, to cover 6/6 is just 1/6 +1/6 +1/6 +1/6 +1/6 +1/6 , or 6 bags
2)
one can was enough for 1/4 of the sprayer, a full sprayer is 1 whole or 4/4, so 1/4 + 1/4 + 1/4 + 1/4 or 4 cans
3)
one potato gives enough for 1/3 for a lighbulb, again, 1 whole is 3/3, so 1/3 +1/3 +1/3 , so 3 potatoes
Answer:
a.
<u>Increasing:</u>
x < 0
x > 2
<u>Decreasing:</u>
0 < x < 2
b.
-1 < x < 2
x > 2
c.
x < -1
Step-by-step explanation:
a.
Function is increasing when it is going up as we go rightward
Function is decreasing when it is going down as we go rightward
We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).
So,
<u>Increasing:</u>
x < 0
x > 2
The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:
<u>Decreasing:</u>
0 < x < 2
b.
When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].
Looking at the graph, it is
from -1 to 2 (x axis)
and 2 to positive infinity
We can write:
-1 < x < 2
x > 2
c.
Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.
This will be the other intervals than the ones we mentioned above in part (b).
Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:
x < -1
Answer:
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
Step-by-step explanation:
Given that,
A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.
From Pythagorean Theorem,
(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+
Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.
∴y²= x²+10²
Differentiating with respect to t
Since the car driving towards the intersection at 13 m/s.
so,
Now
= -12 m/s
Negative sign denotes the distance between the car and the person decrease.
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
?=-40 use -5/k)*(8k here u go
Answer:
The answer is A
Step-by-step explanation:
Supplementary angles are angles which add up to 180°
∠1 and ∠3 add up to 180°, so they are supplementary.
