Answer:
C
Step-by-step explanation:
Answer:
PQR+SQR=180°(angles in a triangle)
75°+SQR=180°
SQR=180°-75°
SQR=105°
Answer:
434567890
Step-by-step explanation:
Answer:
Pythagorean Triples The largest length is always the hypotenuse. If we were to multiply any triple by a constant, this new triple would still represent sides of a right triangle. Therefore, 6, 8, 10 and 15, 20, 25, among countless others, would represent sides of a right triangle.
Step-by-step explanation:
To check if the sides are a right triangle, check if the sum of the squares of the two smaller sides equals the length of the square of the longest side. In other words, check if it works with the Pythagorean theorem: Does 32+42 equal 62 ? Since 25 isn't 36 the triangle is not a right triangle.
Answer:
A) 0.46452
B) 0.82064
Step-by-step explanation:
We solve for question A and B using z score formula
z = (x - μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation.
A) What is the probability that a randomly chosen child has a height of less than 52.85 inches?
x = 52.85 inches, μ = 53.5 inches, σ = 7.3 inches
z = (x - μ)/σ
= 52.85 - 53.5 / 7.3
= -0.08904
Using the z table to find the probability of the z score above.
P(x<52.85) = 0.46452
Therefore, the probability that a randomly chosen child has a height of less than 52.85 inches is 0.46452
B) What is the probability that a randomly chosen child has a height of more than 46.8 inches?
x = 46.8 inches, μ = 53.5 inches, σ = 7.3 inches
z = (x - μ)/σ
= 46.8 - 53.5 / 7.3
= -0.91781
Using the z table to find the probability of the z score above.
P(x<46.8) = 0.17936
P(x>46.8) = 1 - P(x<46.8)
= 1 - 0.17936
= 0.82064
Therefore, the probability that a randomly chosen child has a height of more than 46.8 inches is 0.82064
