I think 5X+1x. Sorry if it's wrong.
Answer:
Hence in 52 weeks he will distribute 156 $ with 3 $ per week from his pay
Step-by-step explanation:
Given:
156 $ to United way for a year.
With each weeks.
To Find:
How much amount he will take for pay for giving to United way.
Solution:
He wants to give money to united way in a year
So there are 365 days per year
And he held money from is his pay every week
So there 7 days per weeks.
Hence Total number of weeks in a year will given by,
=365/7
=52 weeks per year
Now he held every week from his pay to United way
And Total amount to distribute is about 156 $ in 52 weeks.
So Every week amount will be
=156$/52
=3 $ /week
Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.
To find : Area (ΔMNC)
Solution: In Δ ABC, right angled at C,
AC= 6 cm, BC= 8 cm
Using pythagoras theorem
AB² =AC²+ BC²
=6²+8²
= 36 + 64
→AB² =100
→AB² =10²
→AB =10
Also, AM:MN:NB=1:2.5:1.5
Then AM, MN, NB are k, 2.5 k, 1.5 k.
→2.5 k + k+1.5 k= 10
→ 5 k =10
Dividing both sides by 2, we get
→ k =2
MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm
As Δ ACB and ΔMNC are similar by SAS.
So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.
![\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28ACB%29%7D%7BAr%28MNC%29%7D%3D%5B%5Cfrac%7B10%7D%7B5%7D%5D%5E%7B2%7D)
But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]
→ Area(ΔMNC)=24÷4
→Area(ΔMNC)=6 cm²
Answer:
Median and Mode.
Step-by-step explanation:
The data could be represented in table form in ascending order as:
<u>Number of meals</u> <u> Frequency</u>
2 2
3 3
4 2
19 1`
On the basis of the data now we find the mean, median and mode:
Mean= average of the data
Mean=\dfrac{2\times 2+3\times 3+4\times 2+19\times 1}{2+3+2+1}=\dfrac{40}{8}=5
Hence mean is 5.
Median is the central tendency of the data
on looking at our data we see that the Median=3.
also the mode of the data is the entry corresponding to the highest entry.
Hence the highest frequency is 3 and the corresponding value is 3.
Hence, Mode=3
Hence, the most appropriate measure of center for this situation is :
Median and Mode.
