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solmaris [256]
3 years ago
10

How to do break even analysis​

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

To calculate a break-even point based on units: Divide fixed costs by the revenue per unit minus the variable cost per unit. ...

When determining a break-even point based on sales dollars: Divide the fixed costs by the contribution margin.

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Ms. Cassidy plotted the point (2, 3) on Miguel’s graph of y < 2x – 4. She instructed him to change one number or one symbol i
iris [78.8K]

Ms. Cassidy instructed Miguel to change one sign of the graph of y < 2x – 4 so that point (2, 3) can be included in the solution set.

To check which of the given options might Miguel write we check the inequality that holds true for the point (2,3).Substituting x=2 ,y=3 we have:

1) y < 2x – 1

3<2(2)-1

3<3  Not True.

2)y ≤ 2x – 4

3≤ 2(2) -4

3≤ 0  .Not true.

3) y > 2x – 4

3> 2(2)-4

3> 0   True.

4) y < 2x + 4

3<2(2)+4

3<8   True

5) .y < 3.5x – 4

3< 3.5(2)-4

3<3  Not true

6) y < 4x – 4

3<4(2)-4

3<4   True.

Options 3 ,4 ,6 holds true for the point (2,3)


8 0
3 years ago
Read 2 more answers
Which is the same as 10-2?<br> A) 0.0001 <br> B) 0.001 <br> C) 0.01 <br> D) 100
IceJOKER [234]
The correct answer is C. This is because
10^-2 = 1/10^2 which is 0.01
3 0
3 years ago
54 divided by 2,808 the answer an worked out
NemiM [27]
0.019 is the correct answer. I hope this is the answer you are looking for! :)
4 0
3 years ago
SOMEONE PLZZ HELP WITH THESE 2 PROBLEMS ASAP PLSSSSS!!! HELP NEEDED!! WILL MARK BRAINLYIST!!
Pavlova-9 [17]

Good morning Sir/Ma'am!

Answer:

f(r) = 40r + 26

If she can only afford 10 rolls, then the maximum number of nickels Cindy will have is:

f(10) = 40(10) + 26 = 426 nickels


Step-by-step explanation:

Given function  f(r)=40r+26, where r is the number of rolls of nickels she gets.


as it is already mentioned that she can get up to 10 rolls of nickels.


Therefore domain of function contains r ≤10,such that r is a natural number.


i.e.Domain of f(r)=all integers from 1 to 10, inclusive.


Domain of a f(x) is a set of values of x which make function f(x) well defined.



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Have a great day! ( :

5 0
3 years ago
Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at
Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation  that models the height of the gum in centimeters above the ground at any time, t, in seconds.  can be written as:

\mathbf {y = 34cos (\pi (t-1.25))+34}

where;

y =  is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

\mathbf{ \pi} = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m  to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

\mathbf {y = 34cos (\pi (15.6-1.25))+34}

\mathbf {y = 34cos (\pi (14.35))+34}

\mathbf {y = 34cos (45.08)+34}

\mathbf{y = 58.01}

Thus, the  gum is at 58.01 cm from the ground at  t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

\mathbf {y = 34 cos(\pi (t-1.25))+34}

\mathbf{12 = 34 cos ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = cos (\pi(t-1.25))

\dfrac {-22}{34} = cos(\pi(t-1.25))

2.27 = (\pi (t-1.25)

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

\mathbf {y = 34 sin (\pi (t-1.25))+34}

\mathbf{12 = 34 sin ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = sin (\pi(t-1.25))

\dfrac {-22}{34} = sin (\pi(t-1.25))

-0.703 = (\pi(t-1.25))

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0
3 years ago
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