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Murrr4er [49]
3 years ago
8

Consider the expression 6n2 + 2n + 3 . What is the coefficient of n?

Mathematics
1 answer:
ad-work [718]3 years ago
6 0

Answer:

Step-by-step explanation:

2

The coefficient is the number in front of the variable.

So, in this case, the coefficient of n^2 is 6 and of n is 2.

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Lena [83]
The answer is 30 I believe
7 0
2 years ago
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How to count slope on linear equasions<br>​
Naily [24]

Answer:Do rise over run, maybe watch a tutorial on it, pretty simple method

7 0
2 years ago
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Brainliest for correct answer<br><br> A. 2<br><br> B. -2<br><br> C. 1/2<br><br> D. -1/2
seropon [69]

Answer:

B) -2

Step-by-step explanation:

I got the slope by using two points on the line (0,7) and (4,-1)

Slope=y2-y1/x2-x1

(7--1)/(0-4)

=

8/-4

I then simplified 8/-4 to -2

You could also solve by finding the rise over run for two points on the line.

The rise is 2 and the run is -1, making it 2/-1 or -2

8 0
3 years ago
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PLEASE HELP!!!!!The volume of a cube is represented by the expression below, where s is the side length of the cube.
barxatty [35]

Answer:

D. 216 cubic centimetres.

Step-by-step explanation:

The answer is D, because 6 to the 3rd power is 216.  therefore, if the side length is 6, the answer is 216.

7 0
3 years ago
Please Help Me! I will give all my point to who ever answers my question!!!
love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

V=2+\frac{1}{2} t

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

So

V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3

V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2}  }{1} \\V_{avg}=\frac{1}{2}

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when t=1 is 2.5 sec.

3 0
3 years ago
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