1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bond [772]
4 years ago
10

Demont made one fourth pound of rock candy.He will separate the candy into four stacks.If he puts an equal amount of candy in ea

ch sack,what fraction of a pound of candy will be in each sack.
Mathematics
1 answer:
kondor19780726 [428]4 years ago
3 0

Answer:

1/16

Step-by-step explanation:

Demont made one fourth (\frac{1}{4}) pound of rock candy

He separates the candy into four sacks equally.

This is done by dividing the total fraction of candy of a pound of candy made  by the number of sacks

The fraction of a pound of candy that will be in each sack therefore is:

\frac{1}{4}\div  4= \frac{1}{4}X\frac{1}{4}=\frac{1}{16}

Therefore, One-Sixteenth of a pound of candy will be in each of the sack.

You might be interested in
Given that set A has 48 elements and set B has 21 elements, determine each of the following. (a) The maximum possible number of
yKpoI14uk [10]

Answer:  The required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

Step-by-step explanation:  We are given that the set A has 48 elements and the set B has 21 elements.

(a) To determine the maximum possible number of elements in A ∪ B.

If the sets A and B are disjoint, that is they do not have any common element. Then, A ∩ B = { }   ⇒   n(A ∩ B) = 0.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-0=69.

So, the maximum possible number of elements in  A ∪ B is 69.

(b) To determine the minimum possible number of elements in A ∪ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then,  n(A ∩ B) = 21.

From set theory, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-21=48.

So, the minimum possible number of elements in  A ∪ B is 21.

(c) To determine the maximum possible number of elements in A ∩ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then, n(A ∩ B) = 21.

So, the maximum possible number of elements in  A ∩ B is 21.

(d) To determine the minimum possible number of elements in A ∩ B.

If the sets A and B are disjoint, that is there is no common element in the sets A and B . Then,  n(A ∩ B) = 0.

So, the maximum possible number of elements in  A ∩ B is 0.

Thus, the required answers are

(a) 69,  (b) 21,  (c) 21  and  (d) 0.

6 0
3 years ago
A boy weighs 22.5 kilograms. How much does he weigh in pounds? Use the following conversion: 1 kilogram is 2.2 pounds.
salantis [7]

22.5 x 2.2 = 49.5 pounds

4 0
3 years ago
• Packaging of a product can cost a lot of money. Can you design
podryga [215]

The best arrangement can be

  • 3 rows and 4balls each row

So

  • Length of one row=1.8(4)=7.2cm
  • Width=1.8(3)=5.4cm
  • Height=1.8(2)=3.6cm

So

TSA

  • 2(LB+BH+LH)
  • 2(5.4(7.2)+(7.2)(3.6)+3.6(5.4))
  • 2(84.24)
  • 168.48cm²

Total cost

  • 168.48(0.01)
  • 1.685€
5 0
2 years ago
Can you help me with this assignment​
slamgirl [31]
Where what assignment are you talking about
8 0
3 years ago
Read 2 more answers
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
Other questions:
  • Solve the following equation by completing the square
    7·1 answer
  • Which function in vertex form is equivalent to f(x) = 4 + x2 – 2x? f(x) = (x – 1)2 + 3 f(x) = (x – 1)2 + 5 f(x) = (x + 1)2 + 3 f
    13·1 answer
  • *I thought of a number, added 18, then multiplied the result by 8. I got 16. What was my number?
    9·1 answer
  • Please help i need to redo​
    10·2 answers
  • The average number of siblings that each student has is...
    10·2 answers
  • Rewrite each expression as a single power?
    13·1 answer
  • What was the price per yard of fabric
    6·1 answer
  • The value of 5x(13.5-4.5)
    14·2 answers
  • 12. Find the area of shaded portion in<br>D 11 cm<br>C С<br>13.5 cm<br>A<br>B<br>15 cm​
    15·2 answers
  • A juice company decides to test three different brands of juice. The different brands have been labeled A¸ B¸ and C. The company
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!