What is 10000000000000*10

Find the 76th term of the arithmetic sequences 16 14 12

grigory [225]

Answer:

a₇₆ = - 134

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134

7 0

2 years ago

What is the number if: 50% of 25% of the number is 96 Please answer fast! :)

Over [174]

Answer:

768

Step-by-step explanation:

First multiply by two

Then multiply by four

5 0

2 years ago

Read 2 more answers

Please help!! Needed ASAP!!

yarga [219]

Answer and Explanation:

If, on the other hand, the graph "flexes" or "flattens out" to some degree when it goes to cross the axis, then the zero is of a higher multiplicity; that is, it'll be of multiplicity three, five, or higher.

When a graph doesn't start at 0, it means that the graphs before it is not shown.

For number 4, I'd suggest Graph 3.

For number 3, I'd suggest graph 1.

For number 5, Write something along the lines of "Graph 2 does not show the car stopping slowly, it stops suddenly. Then it starts going really fast and stops suddenly again."

I hoped this helped.

3 0

3 years ago

Given the triangle below, find the value of x

Nataliya [291]

Answer:

I think it is b I’m not quite sure though. Sorry if wrong…

Step-by-step explanation:

6 0

2 years ago

The profit from a business is

GuDViN [60]

First of all we will understand the question!!

The question is saying that you are given a function and you have to find the value of x which will give the maximum profit... Lets solve it by finding the extrema using the vertex

 $\rm \: p(x) = - 5 {x}^{2} + 30x + 8$ 

Identify the coefficients a and b of the quadratic function

 $\rm \: p(x) = { - 5x}^{2} + 30x + 8 \\ \rm \: a = - 5 \: and \: b \: = 30$ 

Since a<0, the function has the maximum value at x, calculated by substituting a and b into x=-b/2a

$\rm \: x = \frac{30}{ 2 \times (- 5)}$

Solve the equation for x

$\rm \: x = 3$

The maximum of the quadratic function is at x=3

3 0

1 year ago