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dmitriy555 [2]
3 years ago
11

What is 3(x+2)=15?????​

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

3

Step-by-step explanation:

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Hey guys, hope your day is going well, can you plz help me with is question thank you, i will give 10 pts.
tankabanditka [31]

theres not picture so like i cant help u with that

5 0
2 years ago
1/x&lt;4x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%7D%20%20%3C%204x" id="TexFormula1" title=" \frac{1}{x} &lt
liraira [26]

Answer:

x>\frac{1}{2} \\x

Step-by-step explanation:

If we solve for 'x' variable, its recommended to multiply 'x' variable in both sides of inequality:

we have \frac{1}{4}< x^{2} \\

This is a quadratic equation, two answer are going to be obtained from here.

since \sqrt{x^{2} } = |x|

Applying square roots to both sides of inequality sign we wil have the following

\sqrt{\frac{1}{4} } < \sqrt{x^{2} }

This leaves to the following

\frac{1}{4}

remember that |x|= +/ - x

so

x>\frac{1}{2} \\x

6 0
3 years ago
Let A = −2 2 1 −3 1 1 2 0 −1 and B = 2 −1 0 1 2 1 −1 −2 4 . Use the matrix-column representation of the product to write each co
BigorU [14]

Answer:

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = \left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]

B= \left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * \left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]  + 1 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-1) \left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]

AB Column 2 = (-1)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + 2\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-2)\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}4\\3\\0\end{array}\right]

AB Column 3 = (0)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + (1)\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + 4\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}6\\5\\-4\end{array}\right]

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

4 0
3 years ago
I don’t get it! It says “Match each division expression to it’s quotient.” So can anyone help with 1/12 / 1/6 ? Please!
natta225 [31]

We have two fractions being divided. When we divide two fractions, we flip the second fraction and multiply

1/12 divided by 1/6 = 1/12 * 6/1

-------

From here we multiply straight across.

The numerators multiply to get 1*6 = 6

The denominators multiply to 12*1 = 12

We end up with 6/12 which reduces to 1/2 when you divide both parts by the GCF 6

<h3>Final Answer:  1/2</h3>
5 0
3 years ago
Shelly has a plan to save $500 for a trip that is 8 weeks away. She already has $50 in her
FromTheMoon [43]

Answer:

She will still need about 450$

Step-by-step explanation:

So from what I have learned, she will need to work in order to get the money, but even when she is working, she may have expenses to pay and she may not make it, but she will because she can do loans and when she earns the money from loans, then she can pay, then she may have left over money she can use while on trip.

3 0
2 years ago
Read 2 more answers
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