The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
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Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
x = 4
Step-by-step explanation:
Since JB is the bisector of AD and the length of AD is given as 24 we can conclude that AZ is 12 (half of AD)
2x + 4 = 12
2x = 8
x = 4
Answer:
No
Step-by-step explanation:
Answer:
hello your answer will be 9/2
Step-by-step explanation:
Slope-intercept form: y = mx + c
y = x + 3 is already in this form.
3x + 3y = -9,
3y = -3x - 9
y = -x - 3.
