Answer:
This is one of the efficient ways to find the number of occurrences of a given number in a list:
<h3><u>def find_num(arr,n):</u></h3><h3><u> return len([count for count in arr if count == n])</u></h3><h3><u>print(find_num([0,1,1,1,0],1))</u></h3>
If you want a simpler version, you can try this:
<h2><u>def find_num(arr,n):</u></h2><h2><u> count = 0 </u></h2><h2><u> for i in range(len(arr)): </u></h2><h2><u> if arr[i]==n: </u></h2><h2><u> count += 1 </u></h2><h2><u> return count</u></h2><h2><u>print(find_num([0,1,1,1,0],1))</u></h2>
This is the simplest method:
<h2><u>
arr = [0,1,1,1,0]</u></h2><h2><u>
print(arr.count(1))</u></h2>
I think I gave you enough examples. This should get you started off easily.
If you need an explanation, I am happy to help you. BTW I started python 6 months back so even I am pretty new to this.
The number of unique processes that are created is in the original process, you get the PID of the child process. In the child process, you get 0.
<h3>What is a Code Segment?</h3>
This refers to the portion of an object file that is in the virtual space of a computer that contains executable instructions.
Hence, we can note that since PID >= 0, then there would be the creation of two identical processes in which the original process returns the PID of the child process, and the output in the child process would be zero.
If we make use of a canonical tag,
p = fork();\\if (0 == p)
{
// We're the child process
}
else if (p > 0)
{
// We're the parent process
}
else
{
// We're the parent process, but the child couldn't be created
}
Read more about code segments here:
brainly.com/question/25781514
#SPJ1
Answer:
to address for setting cost increase of a resource to determine the amount of money needed for a future project to plan for future years operation costs to predict sales based on past growth
That is false. are you doing it on a computer course. <span />
