Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =
2(m∠CEA) ∠CEF is a straight angle. ∠AEF is a right angle.
2 answers:
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Answer:
∠A = 70°
Step-by-step explanation:
I'm... guessing this is what you mean? It would've been helpful if you'd provided pictures.
Since all parallelograms consist of two pairs of vertically opposite angles, ∠A and ∠C are equivalent.
Which means that 2x + 50 = 3x + 40.
In which you solve the equation.
2x + 50 = 3x + 40
-2x -2x
50 = x + 40
-40 -40
x = 10
Now, to find ∠A, substitute x into the equation:
∠A = 2x + 50
x = 10
∠A = 20 + 50
∠A = 70
Hence, ∠A = 70°
