All categories

3 years ago

What is square root of 66

Mathematics

2 answers:

Ilya [14]3 years ago

8 0

The square root is 8.12403840464

vampirchik [111]3 years ago

4 0

The square root of 66 is 8.1240384

You might be interested in

Express x in terms of a, b, and c. X =

Vaselesa [24]

Answer:

$\frac{ac}{a+b} .$

Step-by-step explanation:

1) Δ ADE ~ Δ ABC, then

$\frac{AE}{AC} =\frac{DE}{BC}$ ⇒ $\frac{x}{c} =\frac{a}{a+b};$

$2) \ finally, \ x=\frac{ac}{a+b} .$

8 0

2 years ago

Using the digits 1, 3, 5, 7 at most once, you can make many three-digit numbers. What is the maximum possible sum of two such di

lyudmila [28]

Answer:

1504

Step-by-step explanation:

Given the digits :

1, 3, 5, 7

The maximum possible sum of two distinct three digit numbers formed from the digits above will be the sum of the the two hight possible three digit numbers that can be formed.

Highest three digit number = 753

Next highest = 751

The sum of these two. Values gives :

753 + 751 = 1504

3 0

3 years ago

-4(y − 2) = 12 y = ?

maksim [4K]

Answer:

y=-1

Step-by-step explanation:

Using algebra

$-4(y - 2) = 12\\\\y-2=-3\\\\y=-1$

8 0

3 years ago

Read 2 more answers

Compare each set of numbers using <, > or 3.082 x 105 4.13 x 103 Select one m

Darya [45]

Answer:

$4.13 \times 103 > 3.082 \times 105$

7 0

3 years ago

Which expressions are completely factored? Select each correct answer. 18y^3−6y=3y(6y^2−2) 32y^10−24=8(4y^10−3) 20y^7+10y^2=5y(4

Vladimir79 [104]

Answer:

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ 2nd

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ 4th

Step-by-step explanation:

Complete factorization means the terms in the bracket has no common factor

∵ The expression is 18y³ - 6y

- Find the greatest common factor of the numbers and the variable

∵ The greatest common factor of 18 and 6 is 6

∵ The greatest common factor of y³ and y is y

∴ The greatest common factor is 6y

- Divide each term by 6y to find the terms in the bracket

∴ 18y³ - 6y = 6y(3y² - 1) ⇒ not the same with the answer

∵ The expression is $32y^{10}-24$

∵ The greatest common factor of 32 and 24 is 8

∴ The greatest common factor is 8

- Divide each term by 8 to find the terms in the bracket

∴ $32y^{10}-24$ = 8( $y^{10}-3$ ) ⇒ the same with the answer

∴ The expression $32y^{10}-24$ = 8( $y^{10}-3$ ) is completely factored

∵ The expression is $20y^{7}+10y^{2}$

∵ The greatest common factor of 20 and 10 is 10

∵ The greatest common factor of $y^{7}$ and y² is y²

∴ The greatest common factor is 10y²

- Divide each term by 10y² to find the terms in the bracket

∴ $20y^{7}+10y^{2}=10y^{2}(2y^{5}+1)$ ⇒ not the same with the answer

∵ The expression is $16y^{5}+12y^{3}$

∵ The greatest common factor of 16 and 12 is 4

∵ The greatest common factor of $y^{5}$ and y³ is y³

∴ The greatest common factor is 4y³

- Divide each term by 4y³ to find the terms in the bracket

∴ $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ ⇒ the same with the answer

∴ The expression $16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$ is completely factored

The expressions that completely factored are:

$32y^{10}-24$ = 8( $y^{10}-3$ )

$16y^{5}+12y^{3}=4y^{3}(4y^{2}+3)$

3 0

3 years ago