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-BARSIC- [3]
3 years ago
15

What is the voltage of a battery that powers a light with .43 A and has a resistance of 3.5 ohms? A) 1.505 V Eliminate B) 3.07 V

C) 3.93 V D) 8.13 V
Chemistry
1 answer:
Mrac [35]3 years ago
5 0
To determine the voltage of the battery above, we use Ohm's Law which relates voltage (V), current (I) and resistance (R) in a circuit. It is expressed as V = IR. We calculate as follows:

V = IR
V = .43 A ( 3.5 ohms )
V = 1.505 V

Therefore, the correct answer is option A.
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