Answer:
How many moles Iron(II) Sulfide in 1 grams? The answer is 0.011375270162666.
We assume you are converting between moles Iron(II) Sulfide and gram.
You can view more details on each measurement unit:
molecular weight of Iron(II) Sulfide or grams
The molecular formula for Iron(II) Sulfide is FeS.
The SI base unit for amount of substance is the mole.
1 mole is equal to 1 moles Iron(II) Sulfide, or 87.91 grams.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between moles Iron(II) Sulfide and gram.
Type in your own numbers in the form to convert the units!
Similar chemical formulas
Note that all formulas are case-sensitive. Did you mean to convert one of these similar formulas?
moles FeS to grams
moles FEs to grams
Convert another chemical substance
Convert moles
Iron(II) Sulfide
to grams
Quick conversion chart of moles Iron(II) Sulfide to grams
1 moles Iron(II) Sulfide to grams = 87.91 grams
2 moles Iron(II) Sulfide to grams = 175.82 grams
3 moles Iron(II) Sulfide to grams = 263.73 grams
4 moles Iron(II) Sulfide to grams = 351.64 grams
5 moles Iron(II) Sulfide to grams = 439.55 grams
6 moles Iron(II) Sulfide to grams = 527.46 grams
7 moles Iron(II) Sulfide to grams = 615.37 grams
8 moles Iron(II) Sulfide to grams = 703.28 grams
9 moles Iron(II) Sulfide to grams = 791.19 grams
10 moles Iron(II) Sulfide to grams = 879.1 grams
Explanation:
I looked up the answer Here is the website;
https://www.convertunits.com/from/moles+Iron(II)+Sulfide/to/grams
