Answer:
When hydrogen gas combines with nitrogen to form Ammonia the following chemical reaction will take place. Our equilibrium reaction will be N2(g) + 3H2(g) ⇔ 2NH3(g) + Heat. In this case, Hydrogen and nitrogen react together to form ammonia.
Explanation:
Answer:
Explanation:
The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.
This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .
From the Henderson-Hasselbach equation we have that
pH = pKa + log [A⁻]/[HA]
thus
0.1 ≤ [A⁻]/[HA] ≤ 10
Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.
Now we are equipped to answer our question:
pH range = 3.9 +/- 1 = 2.9 through 4.9
Answer:
Catod: K^(+), H2O
2H2O + 2e^(-) ---> H2 + 2OH^(-) reduction reaction
Anod: I^(-), H2O
2I^(-) ---> I2 + 2e^(-) oxidation reduction
2H2O + 2I^(-) ---> I2 + H2 +2OH^(-) ionic net reaction
Answer:
Statements 1 and 2 are correct.
Explanation:
The microenvironment around a amino acid residue can impact its pKa value according with the Born effect. If there is a positively charged environment, like in the second option, the pKa value will decrease, just as it happens in the histidine residue. So the correct answers are 1 and 2.
The unknown material : gold
<h3>Further explanation </h3>
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
ρ = density
m = mass
v = volume
mass of unknown the material : 15.06 g
volume = 0.78 ml
The density :
materials that match the density: gold
