Answer: 31 (a) 4 32 (a) 5
(b) 7 (b) 3
(c) 5 (c) 5
(d) 3 (d) 2
<u>Significant Figures (sf) Rules:</u>
1) Trailing zeroes are considered significant ONLY If a decimal point is provided.
2) Zeroes between the decimal point and number are NOT significant <u>unless</u> they are between numbers.
3) All digits in scientific notation are counted (disregard the exponent).
31 (a) 508.0 <em>trailing zero so use rule 1 </em> --> sf = 4
(b) 820,400.0 <em>trailing zero so use rule 1 </em> --> sf = 7
(c) 1.0200 x 10⁵ <em>scientific notation so use rule 3</em> --> sf = 5
(d) 807,000 <em>no trailing zeroes so use rule 1</em> --> sf = 3
32 (a) 0.049450 <em>zero between decimal point & #, use rule 2</em> --> sf = 5
(b) 0.000482 <em>zero between decimal point & #, use rule 2</em> --> sf = 3
(c) 3.1587 x 10 ⁻⁸ <em>scientific notation so use rule 3</em> --> sf = 5
(d) 0.0084 <em>zero between decimal point & #, use rule 2</em> --> sf = 2
Chemical changeeee purrrr
Answer : The value of
is, 3
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,

The expression of
will be,
![K_{eq}=\frac{[Y]}{[X]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BY%5D%7D%7B%5BX%5D%7D)
Given:
[X] = 0.75 mol/L
[Y] = 2.25 mol/L
Now put all the given values in the above expression, we get:


Therefore, the value of
is, 3