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liq [111]
4 years ago
9

Great Lakes Packing has two bond issues outstanding. The first issue has a coupon rate of 3.50 percent, a par value of $1,000 pe

r bond, matures in 8 years, has a total face value of $3.6 million, and is quoted at 109 percent of face value. The second issue has a coupon rate of 5.94 percent, a par value of $2,000 per bond, matures in 21 years, has a total face value of $7.9 million, and is quoted at 95 percent of face value. Both bonds pay interest semiannually. The company's tax rate is 40 percent. What is the firm's weighted average aftertax cost of debt
Business
1 answer:
katrin [286]4 years ago
6 0

Answer:

2.9652%

Explanation:

to determine the cost of debt we must use the FMV of the bonds plus the YTM:

first bond:

FMV = 1.09 x $1,000 = $1,090 x 3,600 bonds = $3,924,000

YTM = {C + [(F - P)/n]} / [(F + P)/2] = {17.5 + [(1000 - 1090)/16]} / [(1000 + 1090)/2] = (17.5 - 5.625) / 1045 = 1.136% x 2 = 2.27% annual

second bond:

FMV = 0.95 x $2,000 = $1,900 x 3,950 bonds = $7,505,000

YTM = {C + [(F - P)/n]} / [(F + P)/2] = {59.4 + [(2000 - 1900)/42]} / [(2000 + 1900)/2] = (59.4 + 2.38) / 1950 = 3.168% x 2 = 6.34% annual

total debt = $3,924,000 + $7,505,000 = $11,429,000

weighted average after tax cost of debt:

{($3,924,000/$11,429,000 x 2.27%) + ($7,505,000/$11,429,000 x 6.34%)} x (1 - 0.40) = (0.779% + 4.163%) x 0.6 = 4.942% x 0.6 = 2.9652%

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Thomas Kratzer is the purchasing manager for the headquarters of a large insurance company chain with a central inventory operat
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A) 
<span>To determine the Annual Set-up Cost </span>
<span>Annual set-up cost = (# of orders placed per year) x (Setup or order cost per order)  </span><span>= Annual Demand </span><span># of units in each order ¡Á (Setup or order cost per order)  </span><span>= (D/Q) ¡Á(S) </span>
<span>           = (6000/Q) x (30) </span>
<span>
To determine Annual holding cost = Average inventory level x Holding cost per unit per year </span><span>= (Order Quantity/2) (Holding cost per unit per year) </span>
<span>                           = (Q/2) ($10.00) </span>

<span> </span>
<span>To determine Optimal order quantity is found when annual setup cost equals annual holding cost:  </span><span>(D/Q) x (S) = (Q/2) x (H) </span>
<span>                          (6,000/Q) x (30) = (Q/2) (10) </span>
<span>                                                    =(2)(6,000)(30)
                                                    = Q2 (10) </span>
<span>Q2 = [(2 ¡Á6,000 ¡Á30)/($10)]
      = 36,000 </span>
<span>       =([(2 ¡Á6,000 ¡Á30)/(10)])
       =</span><span>189.736 ¡Ö 189.74 units </span><span>
Hence, EOQ = 189.74 units </span>

<span>B)  </span>
<span>Average inventory level = (Order Quantity/2) </span>
<span>                                      = (189.74) /2
                                      = 94.87 </span>
<span>Average Inventory level =94.87 units </span>

<span>C)  </span>
<span>N= ( Demand/ order quantity)
    = (6000/ 189.736)
    =31.62 </span>
<span>Hence, the optimal number of orders per year = 31.62 </span>

<span>D) </span>
<span>T = (Number of Working Days per year) / (optimal number of orders) </span>
<span>   = 250 days per year / 31.62
   = 7.906 </span>
<span>So, the optimal number of days in between any two orders = 7.91 </span>

<span>E) </span>
<span>Using, (Q) x (H) : </span><span>(189.736 units) x ($10) =$1,897.36 </span>
<span>So, The annual cost of ordering and holding the inventory = $1,897 </span>

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<span>TC = setup cost + holding cost </span>
<span>      = (Dyear/Q) (S) + (Q/2) (H) </span>
<span>      = (6,000/189.74) ($30.00) + (189.74/2) ($10.00) </span>
<span>      = $948.67 + $948.7 </span>
<span>      = 1,897.37
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                       = $600,000 </span>
<span>Total annual inventory cost = $600,000 + $1,897
                                            = $601,897 </span>
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3 years ago
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Answer:

A parameter table was constructed to show the transportation problem and to also obtain an optimal solution.

Explanation:

<u>Solution</u>

(a) the first step is to prepare  the problem as a transportation problem by establishing  the appropriate parameter table

                            1        2          3            Supply

Source    1           31      45      38             400

(Plant)      2          29     41       45             600

               3           32     46      40            400

               4           28     42      M              600

               5           29     43      M              1000

     Demand        600    1000  800

The total supply  is = 400 + 600 + 400+ 600+ 1000= 3000

Total demand is = 600 + 1000 + 800 = 2400

(b) since the problem given is an imbalanced transportation problem,to make it a balance transportation problem we will make use of what is called the dummy destination for this numbers 3000 - 2400 = 600

                  1        2          3                  4 (Dummy)      Supply

Source    1           31      45      38               0                   400

(Plant)      2          29     41       45               0                   600

               3           32     46      40               0                   400

               4           28     42      M                 0                   600

               5           29     43      M                 0                    100

Demand             600    1000  800          600

The positive independent number of  allocations is equal to m+n -1 = 5 + 4-1 =8

This solution is a basic feasible solution called a non -degenerate

The cost of initial transportation is he initial transportation cost=31*400+29*200+41*400+46*400+42*200+M*400+M*400+0*600

=$61400+800M

Note: kindly find an attached document of the part of the solution of the work.

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