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3 years ago

Pls answer questions 8 and 9 PLSSS The test statistic

Mathematics

1 answer:

marusya05 [52]3 years ago

6 0

Answer:

8) B

9) D

*ASSUMING THE ALPHA-LEVELS FOR THESE PROBLEMS IS .05.*

Step-by-step explanation:

8) Left-tailed test means that the alternate hypothesis is x is less than a certain value. The p-value, on the calculator, is normalcdf(-999, -1.83) if it's left-tailed, which is .0336. In that case, we would reject the null hypothesis, because the alpha-level is above our p-value.

9) Two-tailed test means that the alternate hypothesis is x does not equal a certain value. The p-value for this, on the calculator, is normalcdf(1.95,999) times two, because we need both tails. In this case, we would fail to reject the null hypothesis, assuming our alpha-level is .05.

normalcdf(1.95,999) = .0256*2 = .0512.

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siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

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3 years ago