Complete each geometric sequence.<br> B. 40, 120, ___, ___<br> C. 200, 20, 2, ___, 0.02, __

What is the answer negative one times the sum of one and seven times a number, decreased by 6 times the difference of negative s

Setler79 [48]

Answer:

The number is -79.

Step-by-step explanation:

Let's set up equation for the given information.

Let the number as 'x'

Negative 1 times the sum of one and seven times a number x could be written as -1(1+7 x).

Now, 6 times the difference of negative seven and a number could be written as

6(-7-x)

Now,

-1(1+7 x) decreased by 6(-7-x) equals 36

So, we can set up equation as

-1(1+7 x)-6(-7-x)=36

Solve the equation for x

-1-7 x-42+6 x=36

Combine like terms

-x-43 =36

Add both sides 43

-x=79

Divide both sides by -1.

x=79

5 0

3 years ago

Simplify an expression for the area of a rectangle with side lengths 12 and (5/6x+23).

lesantik [10]

Answer:

10x+23 (pretty sure) and the * means multiply

Step-by-step explanation:

$12*(5\6x+23)\\12*5/6x\\12/1*5/6x\\60/6x\\10x+23$

4 0

3 years ago

What is 4(x+3) > -24

ludmilkaskok [199]

Isolate the variable by dividing each side by factors that don't contain the variable.
x > -9

6 0

3 years ago

Read 2 more answers

The angle \theta_1θ

enyata [817]

Answer:

$sin\theta_1 = \dfrac{\sqrt{217}}{19}$

Step-by-step explanation:

It is given that:

$cos\theta_1 = -\dfrac{12}{19}$

And we have to find the value of $sin\theta_1 = ?$

As per trigonometric identities, the relation between $sin\theta\ and \ cos\theta$ can represented as:

$sin^2\theta + cos^2\theta = 1$

Putting $\theta_1$ in place of $\theta$ Because we are given

$sin^2\theta_1 + cos^2\theta_1 = 1$

Putting value of cosine:

$cos\theta_1 = -\dfrac{12}{19}$

$sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}$

It is given that $\theta_1$ is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

$\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}$

8 0

3 years ago

Asap! please help i’ll give brainliest

Kay [80]

Answer:C

Step-by-step explanation: The definition of range is the smallest number subtracted from the largest number. So 21-9 is 12. That shows that C is right

7 0

3 years ago

Complete each geometric sequence. B. 40, 120, ___, ___ C. 200, 20, 2, ___, 0.02, ___

Complete each geometric sequence. B. 40, 120, _, _ C. 200, 20, 2, _, 0.02, _