Identify the inheritance mode of each condition by using the labels to complete the table. labels can be used once, more than on
ce, or not at all.
2 answers:
As question lack major information of pedigree i have attached it in this answer for better understanding.
Answer:
Condition A is autosomal recessive
Condition B is a X- linked recessive
Explanation
We analyze the pedigree by checking the mode of inheritance of each condition.
Question arises here that is conditions are dominant or recessive?
Explanation of arose question
As we know that the requirement for dominant condition is that an affected individual must have one affected parent.
While on the other hand, two healthy parents gave birth to affected child which means this condition is recessive. therefore, from the pedigree we get to know that Recessive condition is the case for both conditions A and condition B.
Another question arises here is the condition is X-linked of autosomal?
Explanation of arose question
As we know from the rules of genetics that if two healthy parents gave birth to affected daughter then it’s an autosomal recessive condition. From the pedigree we see that this is the actual case of condition A.
While on the other hand, if two healthy parents gave birth to affected son this condition will be X-linked. From the pedigree this is the case for condition B.
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The correct option is option (a) 1:16.
The probability of having green and wrinkled seeds in a dihybrid cross for round and yellow seeds is 1:16.
A dihybrid cross is a cross between two different genes that differ in two obeserved traits. A phenotype in a dihybrid cross refers to the physical character exhibited by the organism and the genotype refers to the genetic composition of the organism.
A dihybrid cross for round and yellow seeds can be represented as follows. The phenotype of the parents is plants with round and yellow seeds. Their genotype is RrYy. The gametes formes would be RY, Ry, rY and ry.
Parents - RrYy X RrYy
Gametes - RY, Ry, rY, ry.
A punnette square is a tabular summary of the possible combinations of the paternal and maternal alleles and thus predicting the genotypes of the organisms in a breeding experiment.
With the help of Punnett square for the above cross involving round and yellow seeded plants, the probablilty of genotypes of the organisms in the cross is as follows-
9:16 are the plants exhibiting the phenotype round and yellow.
3:16 are the plants exhibiting the phenotype round and green.
3:16 are the plants exhibiting the phenotype wrinkled and yellow.
1:16 are the plants exhibiting the phenotype wrinkled and green.
Thus, 1:16 is the probability of having a green and wrinkled seeds in a dihybrid cross for round and yellow seeds.
