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sashaice [31]
4 years ago
7

You and your brother argue often about how to safely secure a toddler in a moving car. You insist that special toddler seats are

critical in improving the chances of a toddler surviving a crash. Your brother claims that, as long as his wife is buckled in next to him with a seat belt while he drives, she can hold onto their toddler on her lap in a crash. You decide to perform a calculation to try to convince your brother. Consider a hypothetical collision in which the 13 kg toddler and his parents are riding in a car traveling at 37 mi/h relative to the ground. The car strikes a wall, tree, or another car, and is brought to rest in 0.14 as. You wish to demonstrate to your brother the magnitude of the force necessary for his wife to hold onto their child during the collision. What is the magnitude of this force (in N)
Physics
1 answer:
sergey [27]4 years ago
5 0

Answer:

Force F = 1535.86 N

the force necessary for his wife to hold onto their child during the collision is 1535.86 N

Explanation:

Given;

Mass of toddler m = 13 kg

Velocity v = 37 mi/h = 37 × 0.44704 m/s = 16.54 m/s

Impulse time t = 0.14 seconds

Using the impulse momentum equation,

Impulse = change in momentum

Ft = m(∆v)

Force F = m(∆v)/t

∆v = 16.54 m/s

F = 13×16.54/0.14

Force F = 1535.86 N

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Under which circumstances would protesters’ right to assembly most likely be protected?
ICE Princess25 [194]

Answer:

Explanation:

Mob violence is never protected. Organizers are always careful about not letting things get out of hand. Not D

That remark sort of applies to C as well. Property destruction is never protected.

B is something assemblies are allowed to do. So B.

A falls into the same category as C and D. You may not like the fact that he/she is doing something illegal, but you can't take away their privacy.

7 0
3 years ago
What is the speed of a car that travels 60 meters in 5 seconds
Karolina [17]

Answer:

60 ÷ 5= 12 is the speed, hope it helps

3 0
4 years ago
Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del
Mila [183]

Answer:

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Explanation:

El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:

Distancia horizontal (en metros)

x = x_{o} + v_{o}\cdot t \cdot \cos \theta

Donde:

x_{o} - Posición horizontal inicial, medida en metros.

t - Tiempo, medido en segundos.

v_{o} - Velocidad inicial, medida en metros por segundo.

\theta - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.

Distancia vertical (en metros)

y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}

Donde:

y_{o} - Posición vertical inicial, medida en metros.

g - Constante gravitacional, medida en metros por segundo al cuadrado.

Partiendo de la primera ecuación, se despeja el tiempo:

t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}

Si x = 31\,m, x_{o} = 0\,m, v_{o} = 40\,\frac{m}{s} and \theta = 33^{\circ}, entonces:

t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}

t = 0.924\,s

La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si y_{o} = 0\,m, v_{o} = 40\,\frac{m}{s}, t = 0.924\,s y g = -9.807\,\frac{m}{s^{2}}, entonces:

y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}

y = 15.943\,m

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

3 0
3 years ago
Maximum range of a projectile is 1.6 m. Then the velocity of projection will be..... (g=10m/s)
qaws [65]

Answer:

4 m/s

Explanation:

From the question given above, the following data were obtained:

Maximum range (Rₘₐₓ) = 1.6 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

The initial velocity of the projectile can be obtained as follow:

Rₘₐₓ = u² / g

1.6 = u² / 10

Cross multiply

u² = 1.6 × 10

u² = 16

Take the square root of both side

u = √16

u = 4 m/s

Therefore, the velocity of the projectile is 4 m/s

6 0
3 years ago
HURRY!!! How does a sound wave travel through air?
Sergio039 [100]
Answer is B

Hope this helped!
8 0
3 years ago
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