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Brilliant_brown [7]
3 years ago
10

a car has an initial velocity of 15m/s. How far does it travel in the first 10 seconds with a decelaration of 1m/s?

Physics
1 answer:
cestrela7 [59]3 years ago
5 0
110m/10sec is the answer :P
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Explanation:

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Why doesn't the moon turn black during a total lunar eclipse? Explain your answer​
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How does a concave mirror form an image
vladimir2022 [97]

Answer:

The correct option is (c) "it bounces the light towards a focal point"

Explanation:

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A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k
BigorU [14]

Answer:

Explanation:

Given

Cross-sectional area of two areas is

A_1=15\ cm^2

A_2=670\ cm^2

It is filled with oil of density \rho _0=510\ kg/m^3

mass of car place on Large area M=1100\ kg

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

P_1=P_2

\frac{F_1}{A_1}=\frac{F_2}{A_2}

\frac{mg}{15}=\frac{Mg}{670}

m=1100\times \frac{15}{670}

m=24.62\ kg                            

4 0
3 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.3×109 V and the quantity of charg
Georgia [21]

Answer:

A) ΔU = 3.9 × 10^(10) J

B) v = 8420.75 m/s

Explanation:

We are given;

Potential Difference; V = 1.3 × 10^(9) V

Charge; Q = 30 C

A) Formula for change in energy of transferred charge is given as;

ΔU = QV

Plugging in the relevant values gives;

ΔU = 30 × 1.3 × 10^(9)

ΔU = 3.9 × 10^(10) J

B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.

This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.

Thus;

P.E = K.E

ΔU = ½mv²

Where v is final velocity.

Plugging in the relevant values;

3.9 × 10^(10) = ½ × 1100 × v²

v² = [7.8 × 10^(8)]/11

v² = 70909090.9090909

v = √70909090.9090909

v = 8420.75 m/s

4 0
3 years ago
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