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Elodia [21]
4 years ago
7

An object with high momentum ______.

Physics
1 answer:
Pepsi [2]4 years ago
7 0
The answer should be (b)
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You observe a distant galaxy. you find that a spectral line normally found in the visible part of the spectrum is shifted toward
MrRissso [65]
The galaxy is moving away from you.

6 0
3 years ago
Is a body which is moving in a negative direction but has a positive acceleration speeding up or slowing down?​
melamori03 [73]

Answer:

An object with negative acceleration could be speeding up, and an object with positive acceleration could be slowing down.

Explanation:

hope this helps

have a great day/night

7 0
3 years ago
"Light traveling in a medium with a refractive index 1.11 is incident on a plate of another medium with index of refraction 1.66
Kamila [148]

Answer:

56°

Explanation:

Brewsters angle can be simply derived from

n1sin theta1= n2sintheta2= n2costheta1

because the reflected light will be 100% polarized if it is reflected at an angle 90o to the refracted light. Hence, Brewsters angle is

Tan theta= n2/n1

1.66/1.11= 1.495

Theta = 56°

Explanation:

7 0
3 years ago
A wire, of length L = 4.1 mm, on a circuit board carries a current of I = 1.96 μA in the j direction. A nearby circuit element g
tamaranim1 [39]

Answer:

The magnitude of the magnetic field B is 5.921 T.

Explanation:

Given that,

Length = 4.1 mm

B_{x}=4.9\ G

B_{y}=2.3\ G

B_{z}=2.4\ G

Current I = 1.96\ mu A

We need to calculate the magnetic field

Using formula of magnetic field

B=\sqrt{B_{x}^2+B_{y}^2+B_{z}^2}

Put the value into the formula

B=\sqrt{(4.9)^2+(2.3)^2+(2.4)^2}

B=5.921\ T

Hence, The magnitude of the magnetic field B is 5.921 T.

6 0
3 years ago
A force of 20 N acts on a smaller piston of a hydraulic press with an area of ​​10 dm2. How much force does the liquid act on a
ivann1987 [24]

Answer:

166.67 N

Explanation:

Applying Pascal's principle,

Presure in the smaller piston(P') = Pressure in the bigger piston(P)

But,

Pressure = Force/Area

Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')

Pressure in the bigger piston(P) =  Force applied to the bigger piston(F)/Area of the bigger piston(A)

F'/A' = F/A.................. Equation 1

Make F the subject of the equation

F = F'A/A'.............. Equation 2

From the question,

Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²

Substitute these values into equation 2

F = 20(1000)/120

F = 166.67 N

3 0
3 years ago
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