What property of matter determines how much inertia an object has

Physics

1 answer:

tester [92]3 years ago

4 0

The mass of an object determines the object's inertia.

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Measuring the diameter of a specific object might include which pair of SI units

VLD [36.1K]

Well, the diameter of a circle is simply a length, so your measurement will have units of length. We just have to find an answer that has only units of length.

A). gram, second . . . mass and time. That can't be it.

B). kilogram, ampere . . . mass and current. That can't be it.

C). centimeter, meter . . . both lengths. This one is looking good.

D). candela, mole . . . light intensity and some chemical thing. That can't be it.

So it can't be anything else on this list but <em>C</em> .

8 0

3 years ago

A point charge with a charge q1 = 2.30 μC is held stationary at the origin. A second point charge with a charge q2 = -5.00 μC mo

Alla [95]

Answer:

W = 2.74 J

Explanation:

The work done by the charge on the origin to the moving charge is equal to the difference in the potential energy of the charges.

This is the electrostatic equivalent of the work-energy theorem.

$W = \Delta U = U_2 - U_1$

where the potential energy is defined as follows

$U = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}$

Let's first calculate the distance 'r' for both positions.

$r_1 = \sqrt{(x_1 - x_0)^2 + (y_1 - y_0)^2} = \sqrt{(0.170 - 0)^2 + (0 - 0)^2} = 0.170~m\\r_2 = \sqrt{(x_2 - x_0)^2 + (y_2 - y_0)^2} = \sqrt{(0.250 - 0)^2 + (0.250 - 0)^2} = 0.353~m$

Now, we can calculate the potential energies for both positions.

$U_1 = \frac{kq_1q_2}{r_1^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.170)^2} = -3.57~J\\U_2 = \frac{kq_1q_2}{r_2^2} = \frac{(8.99\times 10^9)(2.3\times 10^{-6})(-5\times 10^{-6})}{(0.3530)^2} = -0.829~J$