Well, collinear points are points in same line,
that is a straight line is formed by connecting them,
here the line segment mE has point A,G,C,E so all these are collinear..
so, option c) E will be answer
hope it helped
One kilowatt-hour = 1000 watts = 1000 joules/second
One hour = 60 × 60 = 3600 seconds
One kWh = 3600 × 1000 joules
One kWh = 36 × 100000 joules
One kWh = 3.6 × 10 × 100000 joules
One kWh = 3.6 × 10⁶ joules
Answer: Second option
Answer: v = 2.53 m/s at E 53.1° S
Explanation:
Conservation of momentum
The 400 g object has no North-South velocity, so the initial momentum in that direction is zero. The total momentum after collision must also be zero
0 = 400(8sin35) + 650vy
vy = -2.82376... m/s
In the East direction
400(10) = 400(8cos35) + 650vx
vx = 2.121097...m/s
v = √(2.12² + 2.82²) = 3.531667... ≈ 2.53 m/s
θ = arctan(vy/vx) = arctan(-2.82/2.12) = -53.087... ≈ E53.1°S
Answer:
6400 m
Explanation:
You need to use the bulk modulus, K:
K = ρ dP/dρ
where ρ is density and P is pressure
Since ρ is changing by very little, we can say:
K ≈ ρ ΔP/Δρ
Therefore, solving for ΔP:
ΔP = K Δρ / ρ
We can calculate K from Young's modulus (E) and Poisson's ratio (ν):
K = E / (3 (1 - 2ν))
Substituting:
ΔP = E / (3 (1 - 2ν)) (Δρ / ρ)
Before compression:
ρ = m / V
After compression:
ρ+Δρ = m / (V - 0.001 V)
ρ+Δρ = m / (0.999 V)
ρ+Δρ = ρ / 0.999
1 + (Δρ/ρ) = 1 / 0.999
Δρ/ρ = (1 / 0.999) - 1
Δρ/ρ = 0.001 / 0.999
Given:
E = 69 GPa = 69×10⁹ Pa
ν = 0.32
ΔP = 69×10⁹ Pa / (3 (1 - 2×0.32)) (0.001/0.999)
ΔP = 64.0×10⁶ Pa
If we assume seawater density is constant at 1027 kg/m³, then:
ρgh = P
(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa
h = 6350 m
Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.
Answer:
In order to understand all three questions one must have knowledge of rotational and transitional motion.
Explanation:
a.
Both energies could be compared by means of their motion,as Ball it self rolling and also moving linearly therefore it has combination of linear and rotational kinetic energy in the mean while block of ice just have linear kinetic energy therefore Basketball have more kinetic energy
in case of Basket ball
in case of Ice
b.
For momentum it is obvious that for basketball their is angular momentum along with linear momentum.
P = m v in case of linear momentum while
L= I w in case of angular momentum where I have rotational inertia and w is the angular velocity
their is no angular momentum in case of an ice block because it was moving in linear motion.
c.
Due to the additional angular momentum conserved in the case of basketball so it has more energy conserved as compared to ice block therefore frictional effect and ramp sloping does not hurt much motion of basketball as compared to ice blocking.
