Plz answer I need help
2 answers:
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Answer:
(- 16.7, 5.2 )
Step-by-step explanation:
let the coordinates of the endpoint be (x , y )
using the midpoint formula
consider the x- coordinate
(x + 1.7) = - 7.5 ( multiply both sides by 2 )
x + 1. 7 = - 7.5 ( subtract 1.7 from both sides )
x = - 16.7
consider the y-coordinate
(y - 4.6 ) = 0.3 ( multiply both sides by 2 )
y - 4.6 = 0.6 ( add 4.6 to both sides )
y = 5.2
endpoint = (- 16.7, 5.2 )
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.
