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denpristay [2]
2 years ago
14

On a coordinate plane, a line goes through (negative 4, 2) and (negative 2, negative 4). Which are solutions of the linear equat

ion? Select all that apply. 3x + y = –10
Mathematics
2 answers:
elena-s [515]2 years ago
8 0

Answer:

The 2nd and last one

Step-by-step explanation:

(-2,-4)

(-5,5)

I did it on edge 2020

hammer [34]2 years ago
3 0

Answer:

Y = (-3) *X - 10

solution for Y =0 ---> X = -10/3

Step-by-step explanation:

Two points:

(Y0 ; X0) = (-4 ; 2)  

(Y1 ; X1) = (-2 ; -4)

There is only one line which pass for both of them, his general expresion is:

y = a*x + b --- (1)

Calculating "a": is the pending of the line.

a = \frac{Y1 - Y0}{X1 - X0} = \frac{(-4) - (2)}{-2 - (-4)} =\frac{-6}{2} = -3

Calculating "b":

Since every point who belongs to the line satisfied the (1) expresion, we can use it for the point (Y1 ; X1) :

Y0 = (-3)*X0 + b  ---> 2 = (-3)*(-4) + b ---> b = -10

<u>Final expresion</u>

Replacing in (1): Y = (-3) *X - 10

Solutions: Y = (-3) *X - 10 = 0 --- > X = -\frac{10}{3}

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2 years ago
Read 2 more answers
F(x)=3x-3<br><br>g(x) 3x^3+5<br>Find F(-3) and g(-2)
astra-53 [7]

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is <em>x</em> = -3 for function f(x)

g(-2) is <em>x</em> = -2 for function g(x)

<u>Step 2: Evaluate</u>

f(-3)

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-3) = 3(-3) - 3
  2. Multiply:                                                                                                             f(-3) = -9 - 3
  3. Subtract:                                                                                                            f(-3) = -12

g(-2)

  1. Substitute in <em>x</em> [Function g(x)]:                                                                         g(-2) = 3(-2)³ + 5
  2. Exponents:                                                                                                        g(-2) = 3(-8) + 5
  3. Multiply:                                                                                                            g(-2) = -24 + 5
  4. Add:                                                                                                                   g(-2) = -19
4 0
3 years ago
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