Question

On a coordinate plane, a line goes through (negative 4, 2) and (negative 2, negative 4). Which are solutions of the linear equation? Select all that apply. 3x + y = –10

Answer 1

Answer:

The 2nd and last one

Step-by-step explanation:

(-2,-4)

(-5,5)

I did it on edge 2020

Answer 2

Answer:

Y = (-3) *X - 10

solution for Y =0 ---> X = -10/3

Step-by-step explanation:

Two points:

(Y0 ; X0) = (-4 ; 2)  

(Y1 ; X1) = (-2 ; -4)

There is only one line which pass for both of them, his general expresion is:

y = a*x + b --- (1)

Calculating "a": is the pending of the line.

$a = \frac{Y1 - Y0}{X1 - X0} = \frac{(-4) - (2)}{-2 - (-4)} =\frac{-6}{2} = -3$

Calculating "b":

Since every point who belongs to the line satisfied the (1) expresion, we can use it for the point (Y1 ; X1) :

$Y0 = (-3)*X0 + b ---> 2 = (-3)*(-4) + b ---> b = -10$

Final expresion

Replacing in (1): $Y = (-3) *X - 10$

Solutions: $Y = (-3) *X - 10 = 0 --- > X = -\frac{10}{3}$