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3 years ago

Find the output, k, when the input, t, is -7−7minus, 7. k = 10t-19k=10t−19

Mathematics

1 answer:

sleet_krkn [62]3 years ago

7 0

The value of k is -89

Explanation:

The given expression is $k=10t-19$

We need to determine the output k, when the input t is -7

<u>Output k:</u>

The value of the output k can be determined by substituting the input $t=-7$ in the expression $k=10t-19$

Thus, we have,

$k=10(-7)-19$

Multiplying the terms 10 and -7, we have,

$k=-70-19$

Simplifying, we get,

$k=-89$

Thus, the value of k is -89

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Answer:

The regression line is not a good model because there is a pattern in the residual plot.

Step-by-step explanation:

Given is a residual plot for a data set

The residual plot shows scatter plot of x and y

The plotting of points show that there is not likely to be a linear trend of relation between the two variables. It is more likely to be parabolic or exponential.

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Also there is not a pattern of linear trend.

D) The regression line is not a good model because there is a pattern in the residual plot.

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3 years ago

Working alone, shayna can harvest a field in 8 hours. John can harvest the same field in 16 hours. How long would it take them i

Alinara [238K]

(1/8)x + (1/16)x = 1
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3 years ago

Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC

Marysya12 [62]

BC is 10 units and AC is $5+5\sqrt{3}$ units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}$
AB is opposite to ∠C
BC is opposite to ∠A
AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ $\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

∵ AB = $5\sqrt{2}$

- Substitute AB and the 3 angles in the rule above

∴ $\frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}$

- By using cross multiplication

∴ (BC) × sin(30) = $5\sqrt{2}$ × sin(45)

∵ sin(30) = 0.5 and sin(45) = $\frac{1}{\sqrt{2}}$

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ $\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

- Substitute AB and the 3 angles in the rule above

∴ $\frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}$

- By using cross multiplication

∴ (AC) × sin(30) = $5\sqrt{2}$ × sin(105)

∵ sin(105) = $\frac{\sqrt{6}+\sqrt{2}}{4}$

∴ 0.5 (AC) = $\frac{5+5\sqrt{3}}{2}$

- Divide both sides by 0.5

∴ AC = $5+5\sqrt{3}$ units

BC is 10 units and AC is $5+5\sqrt{3}$ units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

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4 years ago

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