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ASHA 777 [7]
3 years ago
11

I need help i don’t know which one is right please help

Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer: 12√2

Step-by-step explanation:

This is a 45-45-90 triangle. In this triangle, a and b are equal lengths, therefore hypotenuse, c, is x√2.

Since a and b is 12, c is 12√2.

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Can someone help me solve question 2 and 3?
ale4655 [162]

Answer:

Question 2 = 15 drinks

Question 3 = 7/12

Step-by-step explanation:

Question 2:

For every drink, there are three sizes

Ratio = 1:3

There are 5 flavors

Multiply each side by 5

5:15

15 drinks

Question 3:

5 red, 6 yellow, 8 blue, 3 orange, 2 purple

Possible outcomes = 5 + 6 + 8 + 3 + 2 = 24 possible outcomes

Favourable outcomes = 6 + 8 = 14 favourable outcomes

Fraction = 14/24 = 7/12

If my answer is incorrect, pls correct me!

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3 years ago
If h(x) = 5 x and k(x)=1/x, which expression is equivalent to (koh)(x)?
Lyrx [107]
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x

1) If h(x) = 5x and k(x) = 1/x

Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)

2) If h(x) = 5 + x and k (x) = 1/x

Then (k o h)(x) =k ( h(x) ) = k (5+x) =  1 / [5 + x]
4 0
3 years ago
Read 2 more answers
Which side is adjacent to
Akimi4 [234]

Answer:

Answer is on the pic

Step-by-step explanation:

I hope it's helpful!

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Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

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And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
3 years ago
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GenaCL600 [577]
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