Answer:
P(25 < x < 37) = 0.77
Step-by-step explanation:
Given - If a Variable has a normal distribution with mean 30 and standard deviation 5
To find - find the probability that the variable will be between 25 and 37.
Proof -
Given that,
Mean, μ = 30
S.D, σ = 5
Now,
~ N(0,1)
Now,
P(25 < x < 37)
= 
= P(1 < z < 1.4)
= P(z < 1.4) - P(z < -1)
= 0.9192 - 0.1587
= 0.7605
≈ 0.77
∴ we get
P(25 < x < 37) = 0.77
Rounding it off to the nearest tenth means rounding it off to the first decimal place . so the answer is 6.8
Answer:
P(a junior or a senior)=1
Step-by-step explanation:
The formula of the probability is given by:
P (AB) = P(A)
Where P(A) is the probability of occurring an event A, n(A) is the number of favorable outcomes and N is the total number of outcomes.
In this case, N is the total number of the students of statistics class.
N=18+10=28
The probability of the union of two mutually exclusive events is given by:
Therefore:
P(a junior or a senior) =P(a junior)+P(a senior)
Because a student is a junior or a senior, not both.
n(a junior)=18
n(a senior)=10
P(a junior)=18/28
P(a senior) = 10/28
P(a junior or a senior) = 18/28 + 10/28
Solving the sum of the fractions:
P(a junior or a senior) = 28/28 = 1
Let the other 2 unknown sides be y n z
look at the two smaller triangles inside
y^2 = 12^2 + x^2 and
z^2 = 21^2 + x^2
from the biggest triangle
(12+21)^2 = y^2 + z^2
substituting
(12+21)^2 = (12^2 + x^2) + (21^2 + x^2)
33^2 = 12^2 + 21^2 + 2x^2
2x^2 = (33^2 - 12^2 - 21^2)/2 = 504
x^2 = 252
x = 15.9
ans is B
Base times height times width
