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2 years ago

Factor the expression: 20b - 16

2 answers:

6 0

When factoring this expression 20b-16, find the GCF (greatest common factor) among both terms. For this case, it is 4 which is the GCF. Therefore,

20b - 15 is equal to 4(5b - 4)

The factors of the expression are 4 and 5b-4.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

murzikaleks [220]2 years ago

3 0

I hope this helps you

4 (5b-4)

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HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

1 year ago

Robyn opened a bank account to save her birthday money. it was paying 3.75% interest. then the interest rate went up by 0.65%. h

Savatey [412]

Her new interest rate would be 4.40%

8 0

3 years ago

Read 2 more answers

Evaluate this expression. 5^-3

sweet-ann [11.9K]

Answer:

$\Huge \boxed{\frac{1}{125}}$

Step-by-step explanation:

<h2>Order of operations</h2>

PEMDAS

Parenthesis, exponent, multiply, divide, add, and subtract from left to right.

Do exponent.

$\displaystyle \frac{1}{5^3}$

$\displaystyle 5^3=5\times5\times5=125$

$\displaystyle \frac{1}{125}=125$

$\large \boxed{\frac{1}{125}}$ , which is our answer.

Hope this helps!

4 0

3 years ago

(1/3)9 to the third power =

AlekseyPX

The answer would be
1/3 * 9 = 3,
3^3 = 3*3*3, which then we multiply:
3*3=9, 9*3=27.
27 is the answer.

Hope this helps and have a nice day:)

8 0

3 years ago

Read 2 more answers

Neeeeeeeeeeeeeeeeed heeeeeeeeeeeeeeeeelp!!!!!!!!!!!!!!!!!!!!!!!!

iren [92.7K]

Answer: -6r + 6

Hope this helps :)

4 0

3 years ago

Read 2 more answers