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Nady [450]
3 years ago
12

Factor the expression: 20b - 16

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0
When factoring this expression 20b-16, find the GCF (greatest common factor) among both terms. For this case, it is 4 which is the GCF. Therefore,

20b - 15 is equal to 4(5b - 4)

The factors of the expression are 4 and 5b-4.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
murzikaleks [220]3 years ago
3 0
I hope this helps you



4 (5b-4)
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Vladimir79 [104]
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3 years ago
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10x + .0085x = 280000
GaryK [48]

Answer:

x = 27976.22021

Step-by-step explanation:

10x + .0085x = 280000

Combine like terms

10.0085x = 280000

Divide by 10.0085 on each side

10.0085x /10.0085= 280000/10.0085

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6 0
3 years ago
A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that
ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80.2, \sigma = 11

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63.7 - 80.2}{11}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

93.32% probability that a randomly selected score will be greater than 63.7.

5 0
3 years ago
A bike and skate shop rents bike for $21 per day and pairs of skates for $20 per day. To remain viable, the shop needs to make a
Leya [2.2K]
Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)

Putting (2) into (1), then
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42y + 20y ≥ 362
62y ≥ 362
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The least number of pairs of skates they need to rent each day to make their minimum is 6.
7 0
3 years ago
What is the length of (AB)?
earnstyle [38]
  • AB = 4 units
  • BC = 8 units
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hope it helps...!!!

3 0
2 years ago
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