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Mathematics

2 answers:

AnnyKZ [126]3 years ago

7 0

If a square root is not a perfect square, it is considered an irrational number. None of these are perfect squares, so all of the given square roots are irrational. This means your answer would be "Both are irrational". I hope this helps :)

rewona [7]3 years ago

7 0

sqrt 3 + sqrt 2

sqrt 3 + sqrt 6 are both irrational numbers

Rational Number:

It is a number that can be expressed as the quotient or fraction of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number. The set of all such numbers are referred to as 'the rationals', which is denoted as 'Q'. The decimal expansion of a rational number always either terminates after a finite number of digits or begins to repeat the same finite sequence of digits over and over.

Irrational Number:

A real number that is not rational is called irrational. Irrational numbers include √2, π, e, and θ. The decimal expansion of an irrational number continues without repeating. A set of real numbers is uncountable. Hence, almost all real numbers are irrational.

Hope that helps!!!!! : )

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Here are two datasets:

fiasKO [112]

Answer:

Option a) Mean

Mean is affected a lot by the change in the last observation as the median remains the same.

Step-by-step explanation:

we are given the following in the question:

Data set A: 64, 65, 66, 68, 70, 71, 72

Data set B: 64, 65, 66, 68, 70, 71, 720

For data set A, the mean and median are 68.

For data set B:

Formula:

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1124}{7} = 160.57$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$