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Julli [10]
3 years ago
13

What is the solution to the equation 3(2x + 5) = 3x + 4x? a x = 4 b x = 5 c x = 15 d x = 0

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

x= 15 so the c) is right

Step-by-step explanation:

We can do it like:

3(2x + 5) = 3x + 4x

or 6x + 15 = 7x

-6x+ 6x +15 = -6x+ 7x

or 15 = x

The solution is 15

Hope you understand it.

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According to a report from the United States Environmental Protection Agency, burning one gallon of gasoline typically emits abo
Minchanka [31]

Answer:

B. The mean amount of CO_2 emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg

Step-by-step explanation:

A Type II error is the failure to reject a false null hypothesis.

Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower CO_2 emissions.:

H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}

where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline.

If the null hypothesis is false, then:

H_a: \mu < 8.9 kg

A rejection of the alternate hypothesis above will be a Type II error.

Therefore:

The Type II error is: (B) The mean amount of CO_2  emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.

8 0
3 years ago
Please help me!
Vinil7 [7]
It’s the set of all possible outcomes
7 0
3 years ago
Read 2 more answers
Help ASAP will give brainly for CORRECT ANSWER
Pie

Answer:

2cnd one 3rd one 4th one last one

Step-by-step explanation:

4 0
2 years ago
PLEASE HELP WITH 1-3 ILL MARK U THE BRAINLIEST
sammy [17]

Answer:

1:A(-6,-1) B(-14,0) C(-11,4)

2:D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3:H(-4,1) I(-4, 6) J(0,6) K(0,1)

Step-by-step explanation:

Before we begin, lets define the transformations:

(x, y)

T(a, b) = (x+a, y +b)

Rxaxis = (x, -y)

Ryaxis = (-x, y)

r(180, 0) = (-x, -y)

D.5(1/2x, 1/2y)

R(-90, O) = (-y, x)

1. T. A(6,-1) B(14,0) C(11,4)

   Rx. A(6, 1) B(14,0) C(11,-4)

   r180 A(-6,-1) B(-14,0) C(-11,4)

2. Rx D(-12,-6) E(-4,-6) F(-6, -9) G(-10, -9)

   Ry D(12,-6) E(4,-6) F(6, -9) G(10, -9)

   D.5 D(6,-3) E(2,-3) F(3, -4.5) G(5, -4.5)

3. Rx=1 H(-1,2) I(4, 2) J(4,-2) K(-1,-2)

   T H(1,4) I(6, 4) J(6,0) K(1,0)

   r-90 H(-4,1) I(-4, 6) J(0,6) K(0,1)

4 0
3 years ago
Determine whether the statement is sometimes, always, or never true. If ax+b-4=b and doesn’t equal 0 then x=4/a?
attashe74 [19]

Start with expression ax+b-4=b.

1. Separate terms - with x leave in left side, without x write in right side:

ax=b-b+4,\\ \\ax=4.

2. Divide the last expression by a (a\neq 0):

x=\dfrac{4}{a}.

Answer: this statement is true when a\neq 0.

4 0
3 years ago
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