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olasank [31]
3 years ago
15

Why do you need a balanced equation for stoichiometry?

Chemistry
1 answer:
sashaice [31]3 years ago
4 0
To see the mole to mole ratio. If you have this then you see how many moles are used for other reactants/products in the equation
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Find the weighted average for the three following isotopes:
Phantasy [73]

Answer:

Um is there supposed to be a picture?

Explanation:

6 0
3 years ago
the movement of molecules from an area of low concentration to an area of high concentration occurs in what transport?
solmaris [256]
Movement of molecules from an area of higher concentration to one of lower concentration is called Diffusion
4 0
3 years ago
I need help! how many moles are in 3.4*10^-7 grams of silicon dioxide, SiO2. I got 2.0^17 but I think it's wrong :(
blondinia [14]
Molar mass SiO2 = 28 + 32 = 60 

<span>so moles sand = 3.4 x 10-7 / 60</span>
8 0
3 years ago
There is a small block A and a large block B. Block A is 25 grams. Block B is 25 Grams.If Block A is located on the Moon and Blo
a_sh-v [17]

Answer:

They have the same mass

Explanation:

The two blocks have the same mass. Mass is the quantity of matter contained in a substance. Therefore, the two bodies have the same mass.

The weight is a measure of mass and gravity. The gravity on earth differs from that on the moon. Therefore, the two bodies have different weights.

Their volume is also different since one body is larger than the other. Therefore, density which is the mass per unit volume will also differ.

8 0
3 years ago
Convert 4.50 e23 atoms of CO to grams.
hichkok12 [17]

Answer:

10.4664 grams of CO

Explanation:

Remark

There's a couple of things you must look out for in this question.

1. The use of the term atoms. There are 2 atoms in each mol of CO

2. You need to divide by 2 to find the number of molecules which will lead to moles.

<u>Step one</u>

Divide the number of atoms by 2

4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.

<u>Step Two</u>

Find the number of moles of CO

1 mol of anything is 6.02 * 10^23 molecules in this case

x  = 2.25 * 10^23 molecules

1/x = 6.02 * 10^23/2.25 * 10 ^23            Cross multiply

1 * 2.25 * 10^23 = 6.02*10^23 * x           Divide by 6.02 * 10^23

2.25 * 10 ^ 23 / 6.02 * 10^23 = x

x = .3738 moles of CO

<u>Step Three</u>

Find the gram molecular mass of CO

C = 12

O = 16

1 mole = 12 + 16  = 28 grams.

<u>Step Four</u>

Find the number of gram in 0.3738 mols

1 mol = 28 grams

0.3738 mol = x                Cross multiply

x = 28 * 0.3738

x = 10.4664 grams

7 0
3 years ago
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