Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant = 
T = temperature in Kelvins
K = equilibrium constant
We have :
1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
![\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]](https://tex.z-dn.net/?f=%5CDelta%20G%3D-16%2C700%20J%2Fmol%2B8.314J%2FK%20mol%5Ctimes%20310.15%20K%20%5Cln%5B21.9%5D)
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Order of increasing atomic mass!
hope this helps :)
Answer:
63.9%
Explanation:
moral mass of x (# x ions) -divided by- Moral mass of compound.
% of cl = (35.5g) (2 cl ions) -divided by- 111.1g × 100
%= 63.9%
Answer:
B) The group the atom is located
C) There needs to be 2 Na atoms and 1O atom to form Na2O
<h2>Balance Chemical Equation</h2>
1. N2 + 3 H2 = 2 NH3
2. 2 KCIO3 = 2 KCI + 3 O2
3. 2 NaCI + F2 = 2 CI + 2 NaF
4. 2 H2 + O2 = 2 H2O
5. Pb(OH)2 + 2 HCl = 2 H2O + PbCl2
6. 2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3
7. CH4 + 2 O2 = CO2 + 2 H2O
8. C3H8 + 5 O2 = 3 CO2 + 4 H2O
9. 2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
10. FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl
11. 4 P + 5 O2 = 2 P2O5
12. 2 Na + 2 H2O = 2 NaOH + H2
13. 2 Ag2O = 4 Ag + O2
14. S8 + 12 O2 = 8 SO3
15. 6 CO2 + 6 H2O = C6H12O6 + 6 O2
16. 2 K + MgBr2 = 2 KBr + Mg
17. 2 HCl + CaCO3 = CaCl2 + H2O + CO2
18. HNO3 + NaHCO3 = NaNO3 + H2O + CO2 - already balanced
19. 2 H2O + O2 = 2 H2O2
20. 2 NaNO3 + H2SO4 = Na2SO4 + 2 HNO3
