Answer:
Explanation:
The air 9% mole% methane have an average molecular weight of:
9%×16,04g/mol + 91%×29g/mol = 27,8g/mol
And a flow of 700000g/h÷27,8g/mol = 25180 mol/h
In the reactor where methane solution and air are mixed:
In = Out
Air balance:
91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)
Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>
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The air in the product gas is
95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>
43058 mol air×29g/mol <em>1249 kg air</em>
Percent of oxygen is:
=<em>0,231 kg O₂/ kg air</em>
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I hope it helps!
Answer:
The potential energy decreases whereas the kinetic energy increases.
Answer:
Protein Concentration is 2.82mg/L
Explanation:
According to Beer-Lambert's Law, Absorbance is directly proportional to the concentration.
However, the concentration of a solution can be determined from a calibration curve, in which Absorbance is plotted on the y-axis and the Concentration on the x-axis.
Plotting the best line, the equation of line is used
y = mx + c
where y is absorbance = 0.150
m is slope = 0.0163
x is concentration
c is intercept = 0.104
inserting the values from the question
y = mx + c
0.150 = 0.0163x + 0.104
0.0163x = 0.150 - 0.104
0.0163x = 0.046
Divide both sides by 0.0163
0.0163x/0.0163 = 0.046/0.0163
x = 2.82
Concentration of protein = 2.82 mg/L