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seraphim [82]
4 years ago
7

Which of the following formulas would find the lateral area of a right cone where r is the radius and s is slant height?

Mathematics
2 answers:
matrenka [14]4 years ago
8 0

For a right circular cone, the lateral surface area is given by,

L.S.A. =\pi r\sqrt{h^{2}+r^{2}}

The value of square root of h²+r² is equal to slant height s.

So replacing the value of square root of (h²+r²) by s in the formula for lateral surface area , we have

L.S.A. = pi * r * s

where s is slant height of the given right cone.

Answer: The lateral surface area of a right cone is pi*r*s.

Option C is the correct answer.

grin007 [14]4 years ago
7 0
The answer is C: LA=pi rs
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For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

y = mx + b

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b: It is the cut-off point with the y axis

According to the figure, the line goes through the following points:

(x_ {1}, y_ {1}) :( 8, -10)\\(x_ {2}, y_ {2}): (- 8,10)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {10 - (- 10)} {- 8-8} = \frac {10 + 10 } {- 16} = \frac {20} {- 16} = - \frac {5} {4}

By definition, if two lines are perpendicular then the product of their slopes is -1:

m * - \frac {5} {4} = - 1\\m = \frac {-1} {- \frac {5} {4}}\\m = \frac {4} {5}

Thus, the equation is of the form:

y = \frac {4} {5} x + b

If the line goes through (x, y) :( 5,3)we have:

3 = \frac {4} {5} (5) + b\\3 = 4 + b\\3-4 = b\\-1 = b

Finally, the equation is:

y = \frac {4} {5} x-1

Algebraically manipulating we have:

y + 1 = \frac {4} {5} x\\5y + 5 = 4x\\4x-5y = 5

Answer:

Option A

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