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3 years ago

Which of the following formulas would find the lateral area of a right cone where r is the radius and s is slant height?

Mathematics

2 answers:

matrenka [14]3 years ago

8 0

For a right circular cone, the lateral surface area is given by,

$L.S.A. =\pi r\sqrt{h^{2}+r^{2}}$

The value of square root of h²+r² is equal to slant height s.

So replacing the value of square root of (h²+r²) by s in the formula for lateral surface area , we have

L.S.A. = pi * r * s

where s is slant height of the given right cone.

Answer: The lateral surface area of a right cone is pi*r*s.

Option C is the correct answer.

grin007 [14]3 years ago

7 0

The answer is C: LA=pi rs

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What is the answer to 3 4/5 + 2 3/8=

8090 [49]

Answer:

6 $\frac{7}{40}$

Step-by-step explanation:

original equation: $3\frac{4}{5}+ 2 \frac{3}{8}$

put into mixed numbers: $\frac{19}{5} + \frac{19}{8}$

find the lowest common denominator: 40

adjusted to LCD: $\frac{152}{40} + \frac{95}{40\\}$ $=\frac{247}{40}$

152+ 95= 247

247/40= 6.175

0.175 as a fraction is $\frac{7}{40}$

answer: 6 $\frac{7}{40}$

4 0

3 years ago

Use mathematical induction to prove that for each integer n ≥ 4, 5^n ≥ 2 2^n+1 + 100

anastassius [24]

The given Statement which we have to prove using mathematical induction is

$5^n\geq 2*2^{n+1}+100$

for , n≥4.

⇒For, n=4

LHS

$=5^4\\\\5*5*5*5\\\\=625\\\\\text{RHS}=2.2^{4+1}+100\\\\=64+100\\\\=164$

LHS >RHS

Hence this statement is true for, n=4.

⇒Suppose this statement is true for, n=k.

$5^k\geq 2*2^{k+1}+100$

-------------------------------------------(1)

Now, we will prove that , this statement is true for, n=k+1.

$5^{k+1}\geq 2*2^{k+1+1}+100\\\\5^{k+1}\geq 2^{k+3}+100$

LHS

$5^{k+1}=5^k*5\\\\5^k*5\geq 5 \times(2*2^{k+1}+100)----\text{Using 1}\\\\5^k*5\geq (3+2) \times(2*2^{k+1}+100)\\\\ 5^k*5\geq 3\times (2^{k+2}+100)+2 \times(2*2^{k+1}+100)\\\\5^k*5\geq 3\times(2^{k+2}+100)+(2^{k+3}+200)\\\\5^{k+1}\geq (2^{k+3}+100)+3\times2^{k+2}+400\\\\5^{k+1}\geq (2^{k+3}+100)+\text{Any number}\\\\5^{k+1}\geq (2^{k+3}+100)$

Hence this Statement is true for , n=k+1, whenever it is true for, n=k.

Hence Proved.

4 0

3 years ago

HELP!!!! ASAP

9966 [12]

$\tan \theta = \dfrac{opp}{adj}$

$\tan 70^\circ = \dfrac{39~ft}{x}$

$x \tan 70^\circ = 39~ft$

$x = \dfrac{39~ft}{\tan 70^\circ}$

$x = 14.1948...~ ft$

$Answer: 14.2~ft$

8 0

3 years ago

celia rides the downtown trolley three times every day. there are five trolleys that run on the loop downtown. what is the proba

denis23 [38]

The correct format of the question is as follows

Celia rides the downtown trolley three times every day. there are five trolleys that run on the loop downtown. what is the probability that Celia will ride the number two(#2) trolley on all three trips today?

Answer:

The probability that Celia will be selecting the number two ride for the entire three trips for that day will be 1/125.

Step-by-step explanation:

Celia rides to downtown trolley three times a day everyday, there are five available choices for Celia that means she has five trolleys through which she can travel.

We are asked that we need to use the #2 trolley for all the three rides for that day.

Probability for choosing the #2 ride = 1/5 (as there are five available choices and we need to select only the no 2)

Also we need this #2 ride for all the three rides that means we will be selecting the #2 ride thrice

so our required probability will be = 1/5*1/5*1/5

= (1/5)^3

= 1/125

Therefore the probability that Celia will be selecting the number two ride for the entire three trips for that day will be 1/125.

7 0

2 years ago

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tia_tia [17]

Answer:

5x + 4 ≤ 15

Step-by-step explanation:

Since he has only $15, he cannot surpass this amount, BUT the items he purchase CAN equal the same amount so it'd look like this ≤ 15

$4 of jelly beans is a constant

$5 per pound is a variable : 5x

5x + 4 ≤ 15

5 0

3 years ago