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4 years ago

5

If the length of the minute hand of the clock in London commonly known as “Big Ben” is 11.25’ from the center of the clock to th

e tip of the hand, what is the area swept out by the minute hand as it moves 5 minutes of time?

1 answer:

Elenna [48]4 years ago

3 0

The angle swept out is equal to 1/12 of a full rotation is π/6 radians.

r^2 * theta = π/6 * 11.25^2 = 66.268"

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