If you're rolling 5 dice, and all dice have a 1 on them, then you still have a 4/5 chance that four of the five dice will show 1.
The value of <em>p </em>is 21
Step-by-step explanation:
ΔABC ~ ΔFGH

So, the value of <em>p</em> is 21
<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
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▹ Answer
<em>12</em>
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▹ Step-by-Step Explanation

Hope this helps!
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Brainliest is greatly appreciated!
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Answer:
35 x 7 = 245
Step-by-step explanation:
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.