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Vitek1552 [10]
2 years ago
6

CAN SOMEONE PLEASE HELP ME WITH THIS QUESTION !! 3 √5 + 15 √5

Mathematics
2 answers:
nataly862011 [7]2 years ago
7 0

Answer:

18√5  or Decimal Form: 40.24922359…

Step-by-step explanation:

Eduardwww [97]2 years ago
4 0

Answer:

18√5

Step-by-step explanation:

Collect like terms - (<u>3+15</u>)√5

Add the numbers - <u>18√5</u>

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Lxwxh using your numbers its 3x3x3 or 3³ so your answer is 27
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Trucks in a delivery fleet travel a mean of 110 miles per day with a standard deviation of 38 miles per day. The mileage per day
Montano1993 [528]

Answer: 0.1824

Step-by-step explanation:

Given : The mileage per day is distributed normally with

Mean : \mu=110\text{ miles per day}

Standard deviation :  \sigma=38\text{ miles per day}

Let X be the random variable that represents the distance traveled by truck in one day .

Now, calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 132 miles per day.

z=\dfrac{132-110}{38}\approx0.58

For x= 159 miles per day.

z=\dfrac{159-110}{38}\approx1.29

Now by using standard normal distribution table, the  probability that a truck drives between 132 and 159 miles in a day will be :-

P(132

Hence, the probability that a truck drives between 132 and 159 miles in a day =0.1824

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3 years ago
Hi, can someone please answer this questions, THANKS
aliya0001 [1]

Answer:

supplementary angles add up to 180 degrees and complementary add up to 90 degrees

Step-by-step explanation:

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3 years ago
Maths functions question!!
Marina86 [1]

Answer:

5)  DE = 7 units and DF = 4 units

6)  ST = 8 units

\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units

8)  x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

  • f(x)=-x+3
  • g(x)=x^2-9
  • A = (3, 0)  and C = (-3, 0)

<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.  

To find the x-values of the points of intersection, equate the two functions and solve for x:

\implies g(x)=f(x)

\implies x^2-9=-x+3

\implies x^2+x-12=0

\implies x^2+4x-3x-12=0

\implies x(x+4)-3(x+4)=0

\implies (x-3)(x+4)=0

Apply the zero-product property:

\implies (x-3)= \implies x=3

\implies (x+4)=0 \implies x=-4

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

\implies f(-4)=-(-4)=7

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

\implies g(4)=(4)^2-9=7

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

\implies ST=y_S-y_T=7-(-1)=8

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x.  To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

\implies f(x)-g(x)=QR

\implies -x+3-(x^2-9)=\dfrac{45}{4}

\implies -x+3-x^2+9=\dfrac{45}{4}

\implies -x^2-x+\dfrac{3}{4}=0

\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)

\implies 4x^2+4x-3=0

\implies 4x^2+6x-2x-3=0

\implies 2x(2x+3)-1(2x+3)=0

\implies (2x-1)(2x+3)=0

Apply the zero-product property:

\implies (2x-1)=0 \implies x=\dfrac{1}{2}

\implies (2x+3)=0 \implies x=-\dfrac{3}{2}

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}

Therefore, OM = ³/₂ units.

<h3><u>Part (8)</u></h3>

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

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Larry watched one television program for 1/3 of an hour and then watched another program for 15 min. For what fraction of an hou
forsale [732]
The answer is 7/12 of an hour
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