Using the rules of cosines, the <span>measure of the turn between the second and third legs of the race</span> is given by

$\cos^{-1}\left( \frac{180^2+160^2-140^2}{2\times180\times160} \right)=\cos^{-1}\left( \frac{32,400+26,600-19,600}{57,600} \right) \\ \\ =\cos^{-1}\left( \frac{39,400}{57,600} \right)=\cos^{-1}(0.6840)\approx47^o$

4 0

3 years ago

Read 2 more answers

Use the information and diagram to answer the following question.

nevsk [136]

Answer:

910 ft

Step-by-step explanation:

This question sets up the equation tan20°=x/2,500. Solve for X by multiplying 2,500 on both sides giving you x = 2,500tan20°. Finally, plug that in a calculator and you get 909.92. Round it to the nearest foot and you get 910

5 0

2 years ago