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vlada-n [284]
4 years ago
13

Hi there!!

Mathematics
1 answer:
densk [106]4 years ago
8 0
Well, it depends on what the weight of the test is. Most courses tell you that a test is worth a certain percentage of your grade(i.e. Final Exam is worth 20% of your entire grade). It also depends on what your grades for other assignments were, and how many there were. Try asking your teacher.

The average of your previous grade and the grade you got on your test is 84.5%. Average is the mean, which is calculated by: (91 + 78)/2.
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Use the parabola tool to graph the quadratic function f (x) = 2x2 - 4x + 6.
lubasha [3.4K]

Answer:

Vertex plot is (1,4)

and

second plot point (0,6)

Step-by-step explanation:

You can use the the desmos graph calculator by entering quadratic function f(x) = 2x^2 − 4x + 6

3 0
3 years ago
Solve by elimination <br><br>-8x+8y=19<br><br>-4x+4y=8
Harrizon [31]

Answer: the first one :x=y+ −19 /8

the second one:  x=y−2

Step-by-step explanation:

6 0
3 years ago
Please help me this question​
ANTONII [103]

Answer:

0

Step-by-step explanation:

bcoz 2^5 X 9²=2592

so the difference is 0

5 0
3 years ago
Read 2 more answers
Find the maximum value of y = -2(x - 4)2 - 6. A) -6 B) -4 C) -2 D) 4
otez555 [7]

Y=-2(x-4)^2-6

The -6 makes it shift from origin(0,0) to (0,-6)

Then the -4 inside with x, makes it shift to the right by for, so the center would be now instead of (0,0), (4,-6).

As it has a negative A factor, it is a parabola open downwards, so the center is the maximum value.

Answer: (4,-6)

Hope you get it!

6 0
4 years ago
What is 4b + 6 ≤ 18. I don't know how to solve it and don't know the answer.
wolverine [178]

Answer:

b≤3

Step-by-step explanation:

For this problem, you want to solve it similarly to linear equations.

We start with 4b+6≤18.

Subtracting 6 from both sides gives 4b≤12.

From there, in order to isolate the b, we must divide both sides by 4, leaving b≤3.

**This content involves solving linear inequalities, which you may wish to revise. I'm always happy to help!

6 0
3 years ago
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