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defon
3 years ago
5

Aliyah wants to estimate the value of the quotient of 5.68 x 10^-3 and 8.54 x 10^-9. Which statement about the value is true?

Mathematics
2 answers:
ELEN [110]3 years ago
8 0
I think it’s an ok ok but I don’t think so ima
lesya692 [45]3 years ago
8 0

Answer:

0.66x10^{6}=660,000

Step-by-step explanation:

Choices are not provide, however we can find the quotient.

Given numbers are 5.68x10^{-3} and 8.54x10^{-9}. The quotient would be

\frac{5.68x10^{-3}}{8.54x10^{-9}}=0.66x10^{-3-(-9)}=0.66x10^{-3+9}=0.66x10^{6}

This number is expression a big one, because the power expresses that there's more zeros to the right, specifically, the number would be

0.66x10^{6}=660,000

Therefore, the quotient is

0.66x10^{6}=660,000

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(5,6) and (−5,12) what is the rate of change??
Veseljchak [2.6K]

Answer:

- 0.6

Step-by-step explanation:

Start point: (5,6)

End point: (-5,12)

rate of change = (12-6) / (-5-5) = 6/-10 = - 3/5 = - 0.6

4 0
3 years ago
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2. Carter took 56 seconds to ride his bike a distance of 392 feet. At what rate, in feet per
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Answer: 7 ft/sec

Step-by-step explanation:

To find the speed in feet per second, we divide distance by time.

=392/56= 7

Carter rode his bike at 7 ft/sec

5 0
4 years ago
Is it true that if one of the factors is 0, the product is 1?​
kaheart [24]

Answer:

The Principle of Zero Products states that if the product of two numbers is 0, then at least one of the factors is 0. (This is not really new.) If ab = 0, then either a = 0 or b = 0, or both a and b are 0.

hope it helped

5 0
3 years ago
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Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

4 0
3 years ago
Brainliest if you show how to do the work
solong [7]

Answer:

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Step-by-step explanation:

Please can I have the brainliest

3 0
2 years ago
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