1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka21 [38]
3 years ago
10

Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic

e workers to determine the unproductive time per day devoted to unsolicited e-mail and spam (USA Today, November 13, 2003). The data below show a sample of time in minutes devoted to this task.
2 4 8 4
8 1 2 34
12 1 5 8
5 5 3 4
25 18 4 15

Summarize the data by constructing the following items.
1. Fill in the frequency (0 decimals), the relative frequency (2 decimals), the cumulative frequency (0 decimals) and the cumulative relative frequency (2 decimals) values below.

Class (Minutes) Frequency Relative Frequency Cumulative Frequency Cumulative Relative Frequency
1-5
6-10
11-15
16-20
21-25
26-30
31-34
(Total)

2. Use the ogive graph of these data to answer the questions shown below.
(a) What percentage of office workers spend 5 minutes or less on unsolicited e-mail and spam?
(b) What percentage of office workers spend more than 10 minutes a day on this task?

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

You might be interested in
A book sold 35,100 copies in its first month of release. Suppose this represents 9.2% of the number of copies sold to date. How
inessss [21]

Answer:

Total number of copies sold till date are 381522.

Step-by-step explanation:

It is given in the question the book sold 35100 copies in its first month of release and this number is 9.2% of the number of copies sold till date.

To find is how many copies have been sold.

Let the total number of copies sold be = A

Therefore 9.2% × A = 35100

\frac{9.2}{100}A=35100

A=\frac{35100\times 100}{9.2}

A = 381521.74 ≅381522 copies

3 0
3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

7 0
3 years ago
The number 28 please somebody help me...
MArishka [77]
Where is the persons info
8 0
3 years ago
PLS HELP ITS DUE TODAY! thank u so much :)
Mandarinka [93]

Answer:

150

Step-by-step explanation:

5 0
3 years ago
Help me on this one too
never [62]

Answer:

C) -2.5<3

Hope this helps!

Hope this helps!

6 0
2 years ago
Read 2 more answers
Other questions:
  • If Jerry Adams would normally pay $875 for bodily injury
    11·1 answer
  • Which expression is equivalent to the given expression?<br><br> 4p−8
    6·1 answer
  • Write two equations so that each have variables on both sides and a solution of 1/2
    7·1 answer
  • The diagram below shows a triangular metal plate with sides 4.5cm,6cm and 7.5cm. it has three small circular holes of radius 4mm
    10·1 answer
  • What is the measure &lt;G?
    12·1 answer
  • Riley planed 4 rows of pumpkins. There were 1,205 plants in each row. How many pumpkins plants did Riley plant?
    10·1 answer
  • Willa and her friend decide to hang out at her friend’s house after basketball practice on Friday to listen to a new album by th
    13·2 answers
  • What is the slope of y = -4?
    15·1 answer
  • What is the domain and range of this graph?
    9·1 answer
  • Which ordered pairs make the equation true? 3x+2y=−7 Select each correct answer. (3, −8)
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!