1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka21 [38]
3 years ago
10

Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic

e workers to determine the unproductive time per day devoted to unsolicited e-mail and spam (USA Today, November 13, 2003). The data below show a sample of time in minutes devoted to this task.
2 4 8 4
8 1 2 34
12 1 5 8
5 5 3 4
25 18 4 15

Summarize the data by constructing the following items.
1. Fill in the frequency (0 decimals), the relative frequency (2 decimals), the cumulative frequency (0 decimals) and the cumulative relative frequency (2 decimals) values below.

Class (Minutes) Frequency Relative Frequency Cumulative Frequency Cumulative Relative Frequency
1-5
6-10
11-15
16-20
21-25
26-30
31-34
(Total)

2. Use the ogive graph of these data to answer the questions shown below.
(a) What percentage of office workers spend 5 minutes or less on unsolicited e-mail and spam?
(b) What percentage of office workers spend more than 10 minutes a day on this task?

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

You might be interested in
Help wanted plz and thanks
Oxana [17]
I think it’s (B) lmk if I’m wrong
6 0
3 years ago
The three sides of a triangular lot are represented by x, 2x, and 3x + 2. Find each side if the perimeter of the triangular lot
Svetlanka [38]
To find the perimeter, you would add all the sides.  Because we know the perimeter, we can represent this as an equation that needs solved.

362 = x + (2x) + (3x + 2), combine the like terms
362 = 6x + 2, subtract 2 from both sides
   -2           -2
<u>360</u> = <u>6x</u>, divide both sides by 6
   6       6

x = 60 feet

side 1 = 60 feet
side 2 = 120 feet
side 3 = 182 feet

check your work:  60 + 120 + 182 = 362 feet
7 0
3 years ago
Write to explain how subtracting 4/5 - 3/5 is similar to subtracting 4 -3
kondor19780726 [428]
Subtracting fractions with a common denominator, you subtract only the numerator, which are 4 and 3, and keep the common denominator the same, underneath the fraction. It is just subtracting 4 and 3 and putting them in a fraction, just like 4-3
6 0
3 years ago
Read 2 more answers
I need help I’m stuck on this
arsen [322]

press ask for help i think it my help im also stumped on that

8 0
3 years ago
mikes deli just sold 328 ham sandwiches this week. around how many ham sandwiches did mike sold every day this week?
Alenkasestr [34]

Answer:

46.9

Step-by-step explanation:

328/7 = 46.9

To double check: 46.9 x 7 = 328

Have an amazing day!!

PLEASE RATE!!

4 0
2 years ago
Other questions:
  • Why am I so bad at math!!! Please help me. It would be much appreciated. ☻☺
    7·1 answer
  • Inclusive of a 6.8% sales tax, a diamond ring sold for $2029.20. Find the price of the ring before before the tax was added. Rou
    12·1 answer
  • If a varies inversely as the cube root of b and a=1 when b=64, find b​
    8·1 answer
  • Solving systems of equations with substitution y=4x-3, 4x+5y=9
    10·1 answer
  • What is the approximate value of arcsin(0.58).
    13·1 answer
  • The table shows the height of a tree as it grows what equation in slope intercept form gives the trees height at anytime
    5·2 answers
  • Will give brainlest if correct, and 5 stars.<br><br> Solve for x
    9·2 answers
  • Sophie is training for the triathlon. She swims 40 meters in 50 secs, moving at a constant speed. Sophie wants to know her rate
    13·1 answer
  • Kristin wants to wrap a ribbon around the perimeter of a rectangle. The length is five less than twice the width. The perimeter
    7·1 answer
  • Math please help, it is Aleks
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!