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3 years ago

Please help!

1 answer:

3 0

I’m pretty sure ‘side QR’ should be 50cm since ‘side AB’ measures 50 and they are equal sides. hope that helped, if not let me know :)

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Find the y-intercept<br> - 74 - 7y = -7%

harkovskaia [24]

Answer: -75

Step-by-step explanation:

3 0

2 years ago

A vehicle factory manufactures cars. The unit cost C (the cost in dollars to make each car) depends on the number of cars made.

NeTakaya

Answer:

The minimum cost is $9,105

Step-by-step explanation:

<em>To find the minimum cost differentiate the equation of the cost and equate the answer by 0 to find the value of x which gives the minimum cost, then substitute the value of x in the equation of the cost to find it</em>

∵ C(x) = 0.5x² - 130x + 17,555

- Differentiate it with respect to x

∴ C'(x) = (0.5)(2)x - 130(1) + 0

∴ C'(x) = x - 130

Equate C' by 0 to find x

∵ x - 130 = 0

- Add 130 to both sides

∴ x = 130

∴ The minimum cost is at x = 130

Substitute the value of x in C(x) to find the minimum unit cost

∵ C(130) = 0.5(130)² - 130(130) + 17,555

∴ C(130) = 9,105

∵ C(130) is the minimum cost

∴ The minimum cost is $9,105

4 0

2 years ago

Lucy is on her way home in her car. She has driven 22 miles so far, which is one-half of the way home. What is the total length

Ket [755]

Answer:

Step-by-step explanation:

if 22 miles = 1/2

then, 22 times 2 = 44 miles

ANSWER= 44 miles

5 0

2 years ago

The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =

pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

so that

$v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du$

$\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}$

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is $s(0)=0\,\mathrm m$ . Then its displacement over the time interval [0, 3] is

$s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}$

c) The total distance traveled is the integral of the absolute value of the velocity function:

$s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt$

$v(t)$ for $0\le t$ and $v(t)\ge0$ for $\cos^{-1}\left(-\frac29\right)\le t\le3$ , so we split the integral into two as

$\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt$

$=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt$

$\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}$

4 0

3 years ago

Which is equivalent to Square root 10 3/4 x <br> ?

Mama L [17]

It’s that last one 8 square root 10^3x

3 0

2 years ago