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3 years ago

13

use the formula C equals 5 / 9 f - 32 wherever represents degrees Fahrenheit and C represents degrees in celsius to convert 77 d

egrees Fahrenheit to Celsius show your work

1 answer:

Drupady [299]3 years ago

3 0

Answer:

Value of 77 degree Fahrenheit is 25 degree Celsius.

Step-by-step explanation:

Given:

Fahrenheit = 77 (degree).

To convert in Celsius .

Formula of conversion to be used = $(C) =\frac{5}{9}(F - 32)$

Plugging the values of $F=77$ in the above equation.

We have,

⇒ $(C)=\frac{5}{9}(F -32)$

⇒ $(C)=\frac{5}{9}(77 -32)$

⇒ $(C)=\frac{5}{9}*(45)$

⇒ $(C)=\frac{5*45}{9}$

⇒ $(C)=\frac{225}{9}$

⇒ $(C)=25$ (degrees)

So the value of 77 degrees in Fahrenheit scale is equivalent to 25 degrees in Celsius scale.

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stiv31 [10]

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6 0

3 years ago

For the following system, use the second equation to make a substitution for y in the first equation.

VARVARA [1.3K]

Answer:

Option A: 3x + 5x - 4 = 1

Step-by-step explanation:

Given that:

3x + y = 1 ------------- eq1

y + 4 = 5x ------------ eq2

Now for substitution in eq1 we will get a value of y from eq2:

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Substituting in eq1 we get:

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i hope it will help you!

5 0

3 years ago

Consider the following division of polynomials.

Bond [772]

$x^4=x^2\cdot x^2$ . Multiplying the denominator by $x^2$ gives

$x^2(x^2+2x+8)=x^4+2x^3+8x^2$

Subtracting this from the numerator gives a remainder of

$(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8$

$-x^3=-x\cdot x^2$ . Multiplying the denominator by $-x$ gives

$-x(x^2+2x+8)=-x^3-2x^2-8x$

and subtracting this from the previous remainder gives a new remainder of

$(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8$

This last remainder is exactly the same as the denominator, so $x^2+2x+8$ divides through it exactly and leaves us with 1.

What we showed here is that

$\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}$

$=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}$

$=x^2-x+1$

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

$(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)$

$=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)$

$=x^4+x^3+7x^2-6x+8$

which matches the original numerator.

3 0

2 years ago

Read 2 more answers

Help me please .......

kati45 [8]

Answer:

$\huge\boxed{\sf No}$

Step-by-step explanation:

<u>The ordered pairs for the given relation are:</u>

=> {(6,2)(-1,2)(-1,-1)(4,3)}

Domain => x-inputs of the ordered pairs

Domain => (6,-1,4)

Range => y-inputs of the ordered pairs

Range = (2,-1,3)

Since, <em>the values in the domain (-1) are being repeated, this relation is not a function.</em>

<em />

Hope this helped!

~AnonymousHelper1807

6 0

3 years ago

at the football game on friday andrew threw 15 passes. he completed 10 for 120 yards what was his average per completion

Sunny_sXe [5.5K]

Answer:

120 divided by 10 is 12 yards per completion

6 0

2 years ago