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Furkat [3]
3 years ago
5

We know 4 times 9 = 36

Mathematics
2 answers:
ratelena [41]3 years ago
8 0
9 is NOT a multiple of 36. 36 is a multiple of 9. Multiples go..9,18,27,36 so 36 would be 36,72,108... 36 is not a factor of 4. Factors of 4 are 1,2,4. The only correct answer is 9 is a factor of 36.
omeli [17]3 years ago
6 0
Hello!

So, 9 is a multiple of 36, we know that much.
36 is NOT a factor of four.
9 is a factor of 36.
So, check the first box and the third box.

Have a wonderful day!  :)

-L
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To convert mi/h to ft/sec, multiply it to 1.466.

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5 0
3 years ago
Can someone explain I’m confused ‍♂️
coldgirl [10]

Answer:

x = 2000

y = 30000

y-intercept = 30000

slope = 15

one point = (2000 , 30000)

that is as far as I got. Sorry that I couldn't help more. :C

Step-by-step explanation:


4 0
2 years ago
You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

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the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

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Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
2 years ago
If t+8= -12, what is the value of t+1
forsale [732]
T = -20 so
t+1= -20 + 1
= -19
5 0
3 years ago
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